Chapter 5 - WebRing
Chapter 5 - WebRing
Chapter 5 - WebRing
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CHAPTER 5. MAGNETIC SYSTEMS 239<br />
– J – J + J + J<br />
Figure 5.3: The four possible microstates of the N = 2 Ising chain.<br />
and one spin down with energy +J (see Figure 5.3). Thus Z2 is given by<br />
Z2 = 2e βJ +2e −βJ = 4coshβJ. (5.37)<br />
In the same way we can enumerate the eight microstates for N = 3. We find that<br />
Z3 = 2e 2βJ +4+2e −2βJ = 2(e βJ +e −βJ ) 2<br />
(5.38a)<br />
= (e βJ +e −βJ )Z2 = (2coshβJ)Z2. (5.38b)<br />
The relation (5.38b) between Z3 and Z2 suggests a general relation between ZN and ZN−1:<br />
ZN = (2coshβJ)ZN−1 = 2 2coshβJ N−1 . (5.39)<br />
We can derive the recursion relation (5.39) directly by writing ZN for the Ising chain in the<br />
form<br />
ZN = <br />
··· <br />
e βJ N−1 i=1 sisi+1 . (5.40)<br />
s1=±1<br />
sN=±1<br />
The sum over the two possible states for each spin yields 2N microstates. To understand the<br />
meaning of the sums in (5.40), we write (5.40) for N = 3:<br />
Z3 = <br />
e βJs1s2+βJs2s3 . (5.41)<br />
s1=±1 s2=±1 s3=±1<br />
The sum over s3 can be done independently of s1 and s2, and we have<br />
Z3 = <br />
s1=±1 s2=±1<br />
= <br />
<br />
s1=±1 s2=±1<br />
e βJs1s2 e βJs2 +e −βJs2<br />
e βJs1s2 2coshβJs2 = 2coshβJ <br />
<br />
s1=±1 s2=±1<br />
(5.42a)<br />
e βJs1s2 . (5.42b)<br />
We haveused the fact that the cosh function is evenand hence coshβJs2 = coshβJ, independently<br />
of the sign of s2. The sum over s1 and s2 in (5.42b) is Z2. Thus Z3 is given by<br />
in agreement with (5.38b).<br />
Z3 = (2coshβJ)Z2, (5.43)<br />
The analysis of (5.40) for ZN proceeds similarly. We note that spin sN occurs only once in<br />
the exponential, and we have, independently of the value of sN−1,<br />
<br />
sN=±1<br />
e βJsN−1sN = 2coshβJ. (5.44)