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Chapter 5 - WebRing

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CHAPTER 5. MAGNETIC SYSTEMS 273<br />

for the interaction energy between two magnetic moments. Because the electrons responsible for<br />

magnetic behavior are localized near the atoms of a regular lattice in most magnetic materials,<br />

we consider the simple case of two localized electrons. Each electron has spin 1/2 and are aligned<br />

up or down along the axis specified by the applied magnetic field. The electrons interact with<br />

each other and with nearby atoms and are described in part by the spatial wavefunction ψ(r1,r2).<br />

This wavefunction must be multiplied by the spin eigenstates to obtain the actual state of the two<br />

electron system. We denote the basis for the spin eigenstates as<br />

|↑↑〉,|↓↓〉,|↑↓〉,|↓↑〉, (5.139)<br />

where the arrows correspond to the spin of the electrons. These states are eigenstates of the<br />

z-component of the total spin angular momentum 15 ˆ Sz such that ˆ Sz operating on any of the<br />

states in (5.139) has an eigenvalue equal to the sum of the spins in the z direction. For example,<br />

ˆSz|↑↑〉 = 1|↑↑〉 and ˆ Sz|↑↓〉 = 0|↑↓〉. Similarly, ˆ Sx or ˆ Sy give zero if either operator acts on these<br />

eigenstates.<br />

Because electrons are fermions, the basis states in (5.139) are not acceptable because if two<br />

electrons areinterchanged, the wavefunction must be antisymmetric. Thus, ψ(r1,r2) = +ψ(r2,r1)<br />

if the spin state is antisymmetric, and ψ(r1,r2) = −ψ(r2,r1) if the spin state is symmetric. The<br />

simplest normalized linear combinations of the eigenstates in (5.139) that satisfy this condition are<br />

1<br />

√ 2 [|↑↓〉−|↓↑〉], (5.140a)<br />

|↑↑〉, (5.140b)<br />

1<br />

√ [|↑↓〉+|↓↑〉],<br />

2<br />

(5.140c)<br />

|↓↓〉. (5.140d)<br />

The state in (5.140a) is antisymmetric, because interchanging the two electrons leads to minus the<br />

original state. This state has a total spin S = 0 and is called the singlet state. The collection of the<br />

last three states is called the triplet state and has S = 1. If the spins are in the triplet state, then<br />

ψ(r1,r2) = −ψ(r2,r1). Similarly, if the spins are in the singlet state, then ψ(r1,r2) = +ψ(r2,r1).<br />

Hence, when r1 = r2, ψ is zero for the triplet state, and thus the electrons stay further apart, and<br />

their electrostatic energy is smaller. For the singlet state at r1 = r2, ψ is nonzero, and thus the<br />

electrons can be closer to each other, with a larger electrostatic energy. To find a relation between<br />

the energy and the spin operators we note that<br />

ˆS · ˆ S = ( ˆ S1 + ˆ S2) 2 = ˆ S 2 1 + ˆ S 2 2 +2 ˆ S1· ˆ S2, (5.141)<br />

where the operator ˆ S is the total spin. Because both electrons have spin 1/2, the eigenvalues of ˆ S 2 1<br />

and ˆ S 2 2 are equal and are given by (1/2)(1+1/2) = 3/4. We see that the eigenvalue S of ˆ S is zero<br />

for the singlet state and is one for the triplet state. Hence, the eigenvalue of ˆ S 2 is S(S +1) = 0<br />

for the singlet state and (1(1+1) = 2 for the triplet state. Similarly, the eigenvalue S12 of ˆ S1 · ˆ S2<br />

equals −3/4 for the singlet state and 1/4 for the triplet state. These considerations allows us to<br />

write<br />

E = c−JS12, (5.142)<br />

15 We will denote operators with a caret symbol in this section.

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