Simply Sequentially Additive Labeling of Some Special Trees
Simply Sequentially Additive Labeling of Some Special Trees
Simply Sequentially Additive Labeling of Some Special Trees
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<strong>Simply</strong> sequentially additive labeling 6509<br />
f(w1ui) = 2i+9 ; 1 ≤ i ≤ n<br />
n<br />
f(w2vk,j) = 2n+6k+j+6 ; 1 ≤ k ≤ 3 , 1≤ j ≤ 3<br />
Subcase 2.2: n ≡ 1 (mod 3)<br />
Let V(G) = V1 ∪ V2 ∪ V3 ∪ V4 , where V1 = {wi ; 0 ≤ i ≤ n}, V2 = {ui ; 1 ≤ i ≤ n} ,<br />
n<br />
V3 = {vk,j ; 1 ≤ k ≤ [] 3<br />
, 1 ≤ j ≤ 3}, V4 = {vk,1 ; k = 3<br />
and E(G) = E1 ∪ E2 ∪ E3 ∪ E4 , where<br />
E1 = {w0wi ; 1 ≤ i ≤ 4 } , E2 ={w1ui ; 1 ≤ i ≤ n } ,<br />
E3 ={w2vk,j ; 1 ≤ k ≤ []<br />
3<br />
n+ 2 }<br />
n , 1 ≤ j ≤ 3 } and E4 = {w2vk,1 ; k = 3<br />
For 0 ≤ i ≤ 4, assign the label to wi and w0wi as in subcase 2.1.<br />
⎧11<br />
f(ui ) = ⎨<br />
⎩2(i<br />
+ 5)<br />
;<br />
;<br />
i = 1<br />
2 ≤ i ≤ n<br />
⎧2n<br />
+ 6k + j + 5 ;<br />
f(vk,<br />
j)<br />
= ⎨<br />
⎩10;<br />
For 0 ≤ i ≤ 4<br />
n-1<br />
1 ≤ k ≤ 3 ; 1 ≤ j ≤ 3<br />
n+<br />
2 k = 3 ; j = 1<br />
⎧12<br />
;<br />
f(w1 u i ) = ⎨<br />
⎩ 2i + 11 ;<br />
i = 1<br />
2 ≤ i ≤ n<br />
⎧2n<br />
+ 6k + j + 8 ;<br />
f(w 2v<br />
k, j)<br />
= ⎨<br />
⎩13;<br />
n-1<br />
1 ≤ k ≤ 3<br />
n+<br />
2 k = 3<br />
; 1 ≤ j ≤ 3<br />
; j = 1<br />
Subcase 2.3: n ≡ 2 (mod 3)<br />
Let V(G) and E(G) be defined as in case 1.<br />
f(w0) = n+3 ,f(w1) = 1, f(w2) = n + 5 , f(w3) = 4 , f(w4) = 5<br />
⎧2<br />
; i = 1<br />
⎪<br />
⎪<br />
2(i + 1) ; 2 ≤ i ≤<br />
+<br />
f(u ) = ⎨2n<br />
+ 9 ; i =<br />
⎪<br />
+<br />
2n + 12; i = 2 ⎪<br />
⎩(5n<br />
+ 2i + 21) 2 ;<br />
3 n<br />
2 1 n<br />
i<br />
f(w0w1) = n + 4 , f(w0w2) = 2n+8,<br />
f(w0w3) = n + 7 , f(w0w4) = n + 8 ,<br />
f(w 2 i<br />
⎧2n<br />
+ 11<br />
v ) = ⎨<br />
⎩2n<br />
+ i + 12<br />
;<br />
;<br />
2 1 - n<br />
n+<br />
5<br />
2<br />
⎧3<br />
; i = 1<br />
⎪<br />
⎪<br />
2i + 3 ; 2 ≤ i ≤<br />
f(w u ) = ⎨2n<br />
+ 10 ; i =<br />
⎪<br />
+<br />
2n + 13;<br />
i =<br />
⎪<br />
⎩(5n<br />
+ 2i + 23) 2 ;<br />
n<br />
n<br />
1<br />
i<br />
+<br />
2 1<br />
2 1 - n<br />
≤ i ≤ n<br />
2<br />
n+<br />
5<br />
2<br />
3<br />
≤ i ≤ n<br />
i = 1<br />
2 ≤ i ≤ n<br />
)<br />
f(v i<br />
⎧n<br />
+ 6<br />
= ⎨<br />
⎩n<br />
+ i + 7<br />
n+ 2 }<br />
;<br />
;<br />
i = 1<br />
2 ≤ i ≤ n