q - Rosario Toscano - Free
q - Rosario Toscano - Free
q - Rosario Toscano - Free
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Constrained case: the welded beam design problem. HKA was compared to other<br />
metaheuristics specifically designed for solving constrained problems. In these experiments,<br />
HKA handles constraints via a new objective function which includes penalty functions (see<br />
relation (2)).<br />
A welded beam is designed for minimum cost subject to constraints on shear stress τ (q),<br />
bending stress in the beam σ (q), buckling load on the bar Pc, end deflection of the beam δ (q), and<br />
side constraints (Rao, 1996). There are four design variables as shown in Figure 10: h (denoted<br />
q1), l (denoted q2), t (denoted q3) and b (denoted q4), q = [q1, q2, q3, q4] T .<br />
Figure 10 - Welded beam design problem.<br />
The problem can be mathematically formulated as follows:<br />
Minimize 2<br />
J ( q)<br />
= ( 1+<br />
c1)<br />
q1<br />
q2<br />
+ c2q3q4<br />
( L + q2)<br />
Subject to: g ( q)<br />
= τ ( q)<br />
−τ<br />
≤ 0<br />
Where:<br />
τ ( q)<br />
=<br />
6PL<br />
σ ( q)<br />
= , 2<br />
q q<br />
1<br />
g ( q)<br />
= σ ( q)<br />
−σ<br />
2<br />
g ( q)<br />
= q − q<br />
3<br />
4<br />
5<br />
6<br />
7<br />
1<br />
1<br />
1<br />
4<br />
≤ 0<br />
2<br />
1<br />
3<br />
≤ 0<br />
g ( q)<br />
= c q + c q q ( L + q ) − 5 ≤ 0<br />
g ( q)<br />
= h<br />
min<br />
max<br />
4<br />
− q ≤ 0<br />
g ( q)<br />
= δ ( q)<br />
−δ<br />
max<br />
max<br />
≤ 0<br />
g ( q)<br />
= P − Pc(<br />
q)<br />
≤ 0<br />
2 q2<br />
2<br />
τ1<br />
+ 2τ<br />
1τ<br />
2 + τ 2 ,<br />
2R<br />
⎛ q2<br />
⎞<br />
M = P⎜<br />
L + ⎟,<br />
⎝ 2 ⎠<br />
4<br />
3<br />
R =<br />
3<br />
4PL<br />
δ ( q)<br />
= , 2<br />
Eq q<br />
τ =<br />
P<br />
2<br />
q2<br />
⎛ q1<br />
+ q3<br />
⎞<br />
+ ⎜ ⎟ ,<br />
4 ⎝ 2 ⎠<br />
4<br />
3<br />
h<br />
1<br />
t<br />
2<br />
2q<br />
q<br />
1<br />
2<br />
l<br />
2<br />
,<br />
MR<br />
τ 2 =<br />
I<br />
⎪⎧<br />
I = 2⎨<br />
⎪⎩<br />
2<br />
4.<br />
013E<br />
q3<br />
q<br />
Pc(<br />
q)<br />
=<br />
2<br />
L<br />
⎡ 2<br />
2<br />
q<br />
⎤⎪⎫<br />
2 ⎛ q1<br />
+ q3<br />
⎞<br />
2q1q2<br />
⎢ + ⎜ ⎟ ⎥⎬<br />
⎢⎣<br />
12 ⎝ 2 ⎠ ⎥⎦<br />
⎪⎭<br />
6<br />
4<br />
L<br />
/ 36<br />
P<br />
b<br />
⎛ q<br />
⎜ 3<br />
⎜<br />
1−<br />
⎝ 2L<br />
E<br />
4G<br />
⎞<br />
⎟<br />
⎠<br />
(29)<br />
(30)