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On Spatial Processes and Asymptotic Inference under Near$Epoch ...

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hence w.l.g. we can take di;n = 1. Furthermore, by Assumption 6(b) the input<br />

process " is -mixing, <strong>and</strong> the -mixing coe¢ cients satisfy Assumption 4(b).<br />

Consequently (C.2) follows directly from Theorem 2 applied to qi;n(Zi;n; ).<br />

Next observe that by Proposition 1 of Jenish <strong>and</strong> Prucha (2009), Assumption<br />

6(c) implies that qi;n is L0 stochastically equicontinuous on , i.e., for every<br />

" > 0<br />

1<br />

lim sup<br />

n!1 jDnj<br />

X<br />

P<br />

i2Dn<br />

sup<br />

( ; )<br />

jqi;n(Zi;n; ) qi;n(Zi;n; )j > "<br />

!<br />

! 0 as ! 0:<br />

Furthermore, in light of Assumption 6(a) the qi;n(Zi;n; ) clearly satisfy the<br />

domination condition postulated by the ULLN in Jenish <strong>and</strong> Prucha (2009),<br />

stated as Theorem 2 in that paper. Given that we have already veri…ed the<br />

pointwise LLN in (C.2) it now follows directly from that theorem that<br />

1 P<br />

sup jRn( ) ERn( )j<br />

2<br />

p ! 0 (C.3)<br />

with Rn( ) = jDnj i2Dn qi;n(Zi;n; ), <strong>and</strong> that the ERn( ) are uniformly<br />

equicontinuous on in the sense that<br />

lim sup sup<br />

n!1 2<br />

sup<br />

( ; )<br />

To prove (C.1) observe that<br />

sup<br />

2<br />

sup<br />

2<br />

sup<br />

2<br />

jERn( ) ERn( )j ! 0 as ! 0:<br />

Qn( ) Q n( ) (C.4)<br />

jRn( ) 0 P Rn( ) ERn( )P ERn( )j + sup jRn( )<br />

2<br />

0 (Pn P )Rn( )j<br />

jRn( ) 0 P Rn( ) ERn( )P ERn( )j + 2 sup jRn( )j<br />

2<br />

2 jPn P j :<br />

Furthermore observe that Assumption 6(a) we have E [sup 2 jqi;n(Zi;n; )j]<br />

K <strong>and</strong> E [sup 2 jqi;n(Zi;n; )j] 2 K for some …nite constant K. Thus<br />

<strong>and</strong><br />

sup<br />

2<br />

E jRn( )j E sup jRn( )j jDnj<br />

2<br />

E sup jRn( )j<br />

2<br />

2<br />

jDnj<br />

jDnj<br />

2 X<br />

i;j2Dn<br />

2 X<br />

i;j2Dn<br />

E sup<br />

2<br />

"<br />

1 X<br />

i2Dn<br />

E sup jqi;n(Zi;n; )j K (C.5)<br />

2<br />

jqi;n(Zi;n; )j sup jqj;n(Zj;n; )j (C.6)<br />

2<br />

E sup jqi;n(Zi;n; )j<br />

2<br />

2 # 1=2 "<br />

E sup jqj;n(Zj;n; )j<br />

2<br />

Now consider the …rst terms on the r.h.s. of the last inequality of (C.4). From<br />

(C.5) we see that E jRn( )j takes on its values in a compact set. Given (C.3) it<br />

32<br />

2 # 1=2<br />

K:

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