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Polarization and Polarization Controllers - NTNU

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where + denotes right-h<strong>and</strong>ed circular polarization.<br />

2.3 Inner Product <strong>and</strong> Orthogonality<br />

Two normalized polarization states J 1 <strong>and</strong> J 2 are called orthogonal if their inner product defined as<br />

* *<br />

J1 xJ<br />

2x<br />

+ J1y<br />

J 2 y<br />

J =<br />

(14)<br />

1 J 2<br />

is equal to zero. * denotes complex conjugation. Two useful observations are:<br />

2 J1<br />

J1<br />

J 2<br />

*<br />

J = (15)<br />

<strong>and</strong><br />

J = 1 . (16)<br />

If two vectors are normalized <strong>and</strong> orthogonal, they form an orthonormal set.<br />

1 J 1<br />

2.4 Orthogonal Expansion Basis<br />

An arbitrary Jones vector J can be written as a weighted superposition of two orthonormal Jones<br />

vectors J 1 <strong>and</strong> J 2 (the expansion basis) [1], often using linearly or circularly polarized waves as basis.<br />

J J + , (17)<br />

= 1J<br />

1 + J 2J<br />

2 = J 1 J J 1 J 2 J J 2<br />

where we have indicated that the expansion weights J 1 <strong>and</strong> J 2 are the inner products<br />

J 2<br />

=<br />

J 2<br />

J<br />

J = J <strong>and</strong><br />

. If we want to express linearly polarized light in the basis of circular polarized light, we<br />

can use (11) <strong>and</strong> (13) with (14) to obtain J J J J =1/ 2 <strong>and</strong><br />

+ x = − x<br />

1<br />

J 1<br />

J x<br />

Similarly, J J − J J = −i / 2 <strong>and</strong><br />

+ y = − y<br />

= 1<br />

2<br />

J<br />

( J + + −<br />

). (18)<br />

1<br />

J y = J<br />

2<br />

( J + − −<br />

). (19)<br />

2.5 Changing Expansion Basis<br />

Assuming that we have a set of orthogonal Jones vectors J 1 , J 2 , <strong>and</strong> a second set of Jones vectors J 1 ’<br />

J 2 ’, we can write an arbitrary Jones vector as<br />

' ' ' '<br />

1J1 + J 2J<br />

2 = J1J1<br />

J 2J<br />

2<br />

J = J +<br />

. (20)<br />

The relation between the two sets of expansion basis is now found by taking the inner product with J 1 ’<br />

<strong>and</strong> J 2 ’, producing<br />

4

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