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Inference in first-order logic

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Conversion to CNF<br />

Everyone who loves all animals is loved by someone:<br />

∀x (∀y Animal(y) → Loves(x,y)) → (∃y Loves(y,x))<br />

1. Elim<strong>in</strong>ate biconditionals and implications: p → q ≡ ¬p ∨ q<br />

∀x (¬∀y ¬Animal(y) ∨ Loves(x,y)) ∨ (∃y Loves(y,x))<br />

2. Move ¬ <strong>in</strong>wards: ¬∀x p ≡ ∃x ¬p, ¬∃x p ≡ ∀x ¬p:<br />

∀x (∃y ¬(¬Animal(y) ∨ Loves(x,y))) ∨ (∃y Loves(y,x))<br />

∀x (∃y ¬¬Animal(y) ∧ ¬Loves(x,y)) ∨ (∃y Loves(y,x))<br />

∀x (∃y Animal(y) ∧ ¬Loves(x,y)) ∨ (∃y Loves(y,x))<br />

<strong>Inference</strong> <strong>in</strong> <strong>first</strong>-<strong>order</strong> <strong>logic</strong> – 23

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