Large axial forces - Poznań
Large axial forces - Poznań
Large axial forces - Poznań
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
POZNAŃ UNIVERSITY OF TECHNOLOGY<br />
INSTITUTE OF STRUCTURAL ENGINEERING<br />
DIVISION OF STRUCTURAL MECHANICS<br />
EXERCISE NO. 3<br />
INITIAL STABILITY AND STATIC ANALYSIS WITH LARGE AXIAL<br />
FORCES FOR PLANE FRAMES – MATRIX METHOD<br />
Name<br />
Academic year<br />
________________________________<br />
________________________________<br />
For the frame No. ___ :<br />
1. Find the distribution of <strong>axial</strong> <strong>forces</strong> in the frame subjected to the reference loading (λ = 1) using any of the first-order<br />
methods of static analysis.<br />
2. Calculate the critical loading factor λ cr using the discretisation 1 beam – 1 element. Draw the buckling mode.<br />
3. Calculate nodal displacements and internal <strong>forces</strong> taking into account the second-order effects for the loading corresponding<br />
to ____ % of the calculated critical loading. Carry out 1 iteration.<br />
Geometric stiffness matrices for beam elements<br />
1. Clamped-clamped beam 2. Hinged-clamped beam<br />
~<br />
K<br />
g<br />
N<br />
=<br />
30l<br />
⎡0<br />
0 0 0 0 0 ⎤<br />
⎢<br />
⎥<br />
⎢<br />
0 36 3l<br />
0 − 36 3l<br />
⎥<br />
⎢<br />
2<br />
2<br />
0 3l<br />
4l<br />
0 − 3l<br />
− l ⎥<br />
⎢<br />
⎥<br />
⎢0<br />
0 0 0 0 0 ⎥<br />
⎢<br />
⎥<br />
⎢<br />
0 − 36 − 3l<br />
0 36 − 3l<br />
⎥<br />
⎢<br />
2<br />
2⎥<br />
⎣0<br />
3l<br />
− l 0 − 3l<br />
4l<br />
⎦<br />
~<br />
K<br />
g<br />
N<br />
=<br />
30l<br />
⎡0<br />
0<br />
⎢<br />
⎢<br />
0 36<br />
⎢0<br />
0<br />
⎢<br />
⎢0<br />
0<br />
⎢0<br />
− 36<br />
⎢<br />
⎢⎣<br />
0 6l<br />
0<br />
0<br />
0<br />
0<br />
0<br />
0<br />
0 0 0 ⎤<br />
0 − 36 6l<br />
⎥<br />
⎥<br />
0 0 0 ⎥<br />
⎥<br />
0 0 0 ⎥<br />
0 36 − 6l<br />
⎥<br />
⎥<br />
2<br />
0 − 6l<br />
6l<br />
⎥⎦<br />
3. Clamped-hinged beam<br />
~<br />
K<br />
g<br />
⎡0<br />
0 0 0 0<br />
⎢<br />
⎢<br />
0 36 6l<br />
0 − 36<br />
⎢<br />
2<br />
N 0 6l<br />
6l<br />
0 − 6l<br />
= ⎢<br />
30l<br />
⎢0<br />
0 0 0 0<br />
⎢<br />
⎢<br />
0 − 36 − 6l<br />
0 36<br />
⎢⎣<br />
0 0 0 0 0<br />
0 ⎤<br />
0<br />
⎥<br />
⎥<br />
0⎥<br />
⎥<br />
0 ⎥<br />
0<br />
⎥<br />
⎥<br />
0 ⎥⎦
1 2 3<br />
2 2<br />
2<br />
2<br />
1 1<br />
1<br />
1<br />
k = ___ EA1<br />
1<br />
1<br />
2<br />
4 5 6<br />
2 2<br />
2<br />
1<br />
2<br />
1<br />
1<br />
1<br />
2<br />
2<br />
1<br />
1<br />
7 8 9<br />
2 2<br />
2<br />
2<br />
2<br />
1<br />
k = ___ EA1<br />
1<br />
1<br />
2<br />
1<br />
1<br />
10 11 12<br />
2 2<br />
2 2<br />
2<br />
1<br />
1 1<br />
1<br />
1<br />
1<br />
1<br />
13 14<br />
2<br />
1<br />
1<br />
2<br />
1<br />
2<br />
2<br />
1<br />
Element cross-sections:<br />
1 − ____________________<br />
2 − ____________________