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Linear Matrix Inequalities in Control

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Synthesis (18)<br />

Ga<strong>in</strong> Scheduled H-<strong>in</strong>f <strong>Control</strong>ler<br />

• Ga<strong>in</strong> scheduled H-<strong>in</strong>f controller can be<br />

calculated <strong>in</strong> three steps:<br />

1. After the application of elim<strong>in</strong>ation lemma one can<br />

obta<strong>in</strong> Lapunov matrices X and Y for all vertices of<br />

hypercube.<br />

2. For each vertex of hypercube calculate the vertex<br />

controller.<br />

3. For each value of parameter calculate the<br />

correspond<strong>in</strong>g controller and use it <strong>in</strong> the control.<br />

KSO materiały do wykładu 2008/09 79<br />

Synthesis (19)<br />

Elim<strong>in</strong>ation Lemma<br />

• Def<strong>in</strong>ition. An orthogonal complement of given<br />

matrix N is any maximal rank matrix, such that<br />

T<br />

N N 0 and N N 0.<br />

n k n m<br />

T n n<br />

• Lemma. Let M R , N R , H H R<br />

The follow<strong>in</strong>g statements are equivalent:<br />

m k<br />

1. There exists X R such that<br />

T T T<br />

NXM MX N H 0<br />

2. The follow<strong>in</strong>g two conditions hold<br />

N HN<br />

T<br />

M HM<br />

T<br />

0<br />

0<br />

KSO materiały do wykładu 2008/09 80<br />

Synthesis (20)<br />

Ga<strong>in</strong> Scheduled H-<strong>in</strong>f <strong>Control</strong>ler<br />

Step 1. Solve 2*2 L +1 LMIs for X and Y Lapunov matrices<br />

NX<br />

0<br />

0<br />

I<br />

T<br />

T<br />

XA A X<br />

T<br />

B1<br />

X<br />

C<br />

1<br />

XB1<br />

I<br />

D<br />

11<br />

T<br />

C1<br />

T<br />

D11<br />

I<br />

NX<br />

0<br />

0<br />

I<br />

0<br />

Where:<br />

N X<br />

null( C 2<br />

D21<br />

)<br />

)<br />

NY<br />

0<br />

0<br />

I<br />

T<br />

T<br />

YA AY<br />

C Y<br />

B<br />

1<br />

T<br />

1<br />

T<br />

YC1<br />

I<br />

D<br />

T<br />

11<br />

B1<br />

D11<br />

I<br />

NY<br />

0<br />

0<br />

I<br />

0<br />

N<br />

Y<br />

null<br />

T T<br />

( B2<br />

D12<br />

X<br />

I<br />

I<br />

Y<br />

0<br />

KSO materiały do wykładu 2008/09 81<br />

27

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