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Logic Strand Lecture 3

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Rule of Substitution of Equivalence: If in a tautology we<br />

replace any part of a statement by a statement equivalent to<br />

that part, the result is still a tautology.<br />

Example:<br />

• Determine if P ⇒ (~ Q ∨ P)<br />

is a tautology.<br />

We know: P ⇒ ( Q ⇒ P)<br />

is a tautology and<br />

( P ⇒ Q)<br />

≡~<br />

P ∨ Q<br />

By the rule of substitution<br />

( Q ⇒ P)<br />

≡~<br />

Q ∨ P<br />

Thus, by the rule of substitution of equivalence,<br />

P ⇒ ( Q ⇒ P)<br />

≡ P ⇒ (~ Q ∨ P)<br />

, and hence<br />

P ⇒ (~ Q ∨ P) is also a tautology.<br />

Exercise:<br />

• ~ T ∨ (~ S ∨ T ) a tautology? Yes.<br />

We know ( P ⇒ Q)<br />

≡~<br />

P ∨ Q. So, ( S ⇒ T ) ≡~<br />

S ∨ T and<br />

T ⇒ (~ S ∨ T ) ≡~<br />

T ∨ (~ S ∨ T ) (by RoS).<br />

Hence, ~ T ∨ (~ S ∨ T ) ≡ T ⇒ ( S ⇒ T ) (by SoE).<br />

P ⇒ ( Q ⇒ P) is a known tautology, thus (by (SoE)<br />

T ⇒ ( S ⇒ T ) is a tautology, and since<br />

~ T ∨ (~ S ∨ T ) ≡ T ⇒ ( S ⇒ T ), ~ T ∨ (~ S ∨ T ) is a<br />

tautology.<br />

WUCT121 <strong>Logic</strong> 54

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