23.04.2014 Views

479 Horizontal Motion: The horizontal component of velocity ... - Wuala

479 Horizontal Motion: The horizontal component of velocity ... - Wuala

479 Horizontal Motion: The horizontal component of velocity ... - Wuala

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

91962_05_R1_p0<strong>479</strong>-0512 6/5/09 3:53 PM Page 490<br />

© 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently<br />

exist. No portion <strong>of</strong> this material may be reproduced, in any form or by any means, without permission in writing from the publisher.<br />

*R1–16. <strong>The</strong> block has a mass <strong>of</strong> 50 kg and rests on the<br />

surface <strong>of</strong> the cart having a mass <strong>of</strong> 75 kg. If the spring<br />

which is attached to the cart and not the block is<br />

compressed 0.2 m and the system is released from rest,<br />

determine the speed <strong>of</strong> the block with respect to the cart<br />

after the spring becomes undeformed. Neglect the mass <strong>of</strong><br />

the cart’s wheels and the spring in the calculation. Also<br />

neglect friction. Take k = 300 N>m.<br />

k<br />

B<br />

C<br />

T 1 + V 1 = T 2 + V 2<br />

[0 + 0] + 1 2 (300)(0.2)2 = 1 2 (50)v2 b + 1 2 (75) v2 e<br />

12 = 50 v 2 b + 75 v 2 e<br />

( : + ) ©mv 1 =©mv 2<br />

0 + 0 = 50 v b - 75 v e<br />

v b = 1.5 v e<br />

v c = 0.253 m>s ;<br />

v b = 0.379 m>s :<br />

v b = v c + v b>c<br />

( : + ) 0.379 = -0.253 + v b>c<br />

v b>c = 0.632 m>s :<br />

Ans.<br />

490

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!