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479 Horizontal Motion: The horizontal component of velocity ... - Wuala

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91962_05_R1_p0<strong>479</strong>-0512 6/5/09 3:53 PM Page 493<br />

© 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently<br />

exist. No portion <strong>of</strong> this material may be reproduced, in any form or by any means, without permission in writing from the publisher.<br />

R1–19. At the instant shown, cars A and B travel at speeds<br />

<strong>of</strong> 55 mi>h and 40 mi>h, respectively. If B is decreasing its<br />

speed at 1500 mi>h 2 while A is increasing its speed at<br />

800 mi>h 2 , determine the acceleration <strong>of</strong> B with respect to<br />

A. Car B moves along a curve having a radius <strong>of</strong> curvature<br />

<strong>of</strong> 0.75 mi.<br />

v B 40 mi/h<br />

B<br />

A 30<br />

v A 55 mi/h<br />

(a B ) n = v2 B<br />

r = (40)2<br />

0.75<br />

= 2133.33 mi>h2<br />

a B = a A + a B>A<br />

2133.33 sin 30°i + 2133.33 cos 30°j + 1500 cos 30°i - 1500 sin 30°j<br />

= -800i + (a B>A ) x i + (a B>A ) y j<br />

( : + ) 2133.33 sin 30° + 1500 cos 30° = -800 + (a B>A ) x<br />

(a B>A ) x = 3165.705 :<br />

( + c) 2133.33 cos 30° - 1500 sin 30° = (a B>A ) y<br />

(a B>A ) y = 1097.521 c<br />

(a B>A ) = 2(1097.521) 2 + (3165.705) 2<br />

a B>A = 3351 mi>h 2 = 3.35 A10 3 B mi>h 2<br />

u = tan -1 a 1097.521<br />

3165.705 b = 19.1° a<br />

Ans.<br />

Ans.<br />

493

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