479 Horizontal Motion: The horizontal component of velocity ... - Wuala
479 Horizontal Motion: The horizontal component of velocity ... - Wuala
479 Horizontal Motion: The horizontal component of velocity ... - Wuala
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91962_05_R1_p0<strong>479</strong>-0512 6/5/09 3:55 PM Page 504<br />
© 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently<br />
exist. No portion <strong>of</strong> this material may be reproduced, in any form or by any means, without permission in writing from the publisher.<br />
*R1–36. <strong>The</strong> rocket sled has a mass <strong>of</strong> 4 Mg and travels<br />
v<br />
along the smooth <strong>horizontal</strong> track such that it maintains a<br />
T<br />
constant power output <strong>of</strong> 450 kW. Neglect the loss <strong>of</strong> fuel<br />
mass and air resistance, and determine how far the sled must<br />
travel to reach a speed <strong>of</strong> v = 60 m>s starting from rest.<br />
: + ©F x = m a x ; F = m a = ma v dv<br />
ds b<br />
P = F v = ma v2 dv<br />
ds<br />
b<br />
L P ds = m L v2 dv<br />
s<br />
v<br />
P ds = m v 2 dv<br />
L L<br />
0<br />
Ps = m v3<br />
3<br />
s = m v3<br />
3 P<br />
0<br />
s = 4(103 )(60) 3<br />
3(450)(10 3 ) = 640 m<br />
Ans.<br />
R1–37. <strong>The</strong> collar has a mass <strong>of</strong> 20 kg and can slide freely on<br />
the smooth rod. <strong>The</strong> attached springs are undeformed when<br />
d = 0.5 m. Determine the speed <strong>of</strong> the collar after the<br />
applied force F = 100 N causes it to be displaced so that<br />
d = 0.3 m. When d = 0.5 m the collar is at rest.<br />
k¿ 15 N/m<br />
F 100 N<br />
60<br />
d<br />
k 25 N/m<br />
T 1 +©U 1 - 2 = T 2<br />
0 + 100 sin 60°(0.5 - 0.3) + 20(9.81)(0.5 - 0.3) - 1 2 (15)(0.5 - 0.3)2 - 1 2 (25)(0.5 - 0.3)2 = 1 2 (20)v2 C<br />
v C = 2.36 m>s<br />
Ans.<br />
504