Statistics 1 Revision Notes - Mr Barton Maths
Statistics 1 Revision Notes - Mr Barton Maths
Statistics 1 Revision Notes - Mr Barton Maths
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and the variance of t is <br />
<br />
∑ = <br />
= 1⋅204470743<br />
√1 · 204470743 1 · 097483824 = 1.10 to 3 S.F.<br />
To find , using = <br />
, ⇒ = 5 + 210 = 215.5 to 1 D.P.<br />
<br />
To find the standard deviation of x<br />
s x = 5s t = 5 × 1⋅0974838… = 5⋅49 to 3 S.F.<br />
We would need to multiply the variance by 5 2 = 25<br />
⇒ s x 2 = 25s t 2 = 25 × 1⋅204470743 = 30⋅1 to 3 S.F.<br />
22 14/04/2013 <strong>Statistics</strong> 1 SDB