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Statistics 1 Revision Notes - Mr Barton Maths

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and the variance of t is <br />

<br />

∑ = <br />

= 1⋅204470743<br />

√1 · 204470743 1 · 097483824 = 1.10 to 3 S.F.<br />

To find , using = <br />

, ⇒ = 5 + 210 = 215.5 to 1 D.P.<br />

<br />

To find the standard deviation of x<br />

s x = 5s t = 5 × 1⋅0974838… = 5⋅49 to 3 S.F.<br />

We would need to multiply the variance by 5 2 = 25<br />

⇒ s x 2 = 25s t 2 = 25 × 1⋅204470743 = 30⋅1 to 3 S.F.<br />

22 14/04/2013 <strong>Statistics</strong> 1 SDB

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