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Suggested Solutions to Assignment 2 - Department of Economics

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S d = Y+NFP - C d - G = Y+0 – {200 + 0.6[Y – (20 + 0.2Y)] – 200r} –152<br />

= 0.52Y – 340 +200r<br />

So, S d = 0.52Y – 340 +200r (2)<br />

It is given that<br />

NX = 170 − 0.08Y<br />

− 0. 5e<br />

and I d = 300 − 300r<br />

.<br />

Substituting the functional forms <strong>of</strong> S d ,<br />

d<br />

I , and NX in<strong>to</strong> Eq. (1),<br />

0.52Y – 340 + 200r – (300 – 300r) = 170 – 0.08Y –0.5e.<br />

Rearranging terms and simplifying gives the IS curve:<br />

500r = 810 – 0.5e – 0.6Y<br />

810 5 6<br />

or, r = − e − Y<br />

500 5000 5000<br />

(4) [IS curve]<br />

b) Derive the equation for the LM curve as a function <strong>of</strong> Y, M and P.<br />

The equation for the LM curve is derived from the assets market equilibrium condition<br />

for an open economy, which is<br />

M/P = L (5)<br />

Substituting the given functional form <strong>of</strong> L in<strong>to</strong> Eq. (5),<br />

or,<br />

or,<br />

M/P = 0.5Y – 200r<br />

200r = -M/P +0.5Y<br />

M 5<br />

r = − Y<br />

200 P<br />

2000<br />

(6) [LM curve]<br />

c) What are the general equilibrium (that is, long-run) values <strong>of</strong> output, the real<br />

interest rate, real exchange rate, consumption, investment, net exports, and<br />

the price level? Illustrate the general equilibrium values <strong>of</strong> output and the<br />

real interest rate in the IS-LM-FE diagram.<br />

In the general equilibrium, output equals <strong>to</strong> its full-employment level, which is 1000.<br />

The given general equilibrium value <strong>of</strong> real exchange rate, e = 230.<br />

With e = 230 and Y = 1000, the IS curve (Eq. (4)) gives<br />

r =<br />

810<br />

500<br />

−<br />

5<br />

5000<br />

6<br />

5000<br />

( 230) − ( 1000) = 0. 19<br />

Page 3 <strong>of</strong> 7 Pages

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