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ϕ(<br />
x)<br />
1<br />
−∫ d x sin x ∫ d x<br />
= e x [ ∫ e x d x +<br />
x<br />
1<br />
C]<br />
−ln<br />
x sin x ln x<br />
= e [ ∫ e d x + C]<br />
x<br />
1 sin x<br />
1<br />
= [ ∫ ⋅ xd<br />
x + C]<br />
= ( − cos x + C)<br />
x x<br />
x<br />
ϕ( π ) = 1,<br />
C = π − 1<br />
∴<br />
1<br />
ϕ ( x)<br />
= ( π − 1 − cos x)<br />
x