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Pipe Flow Calculations - Clarkson University

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values recommended for commercial pipes given in a textbook on Fluid Mechanics by F.M.<br />

White is provided at the end of these notes.<br />

Colebrook Equation<br />

1 ⎡ε<br />

/ D 1.26<br />

=− 4.0 log10<br />

⎢ +<br />

f<br />

⎣⎢<br />

3.7 Re f<br />

⎤<br />

⎥<br />

⎦⎥<br />

Zigrang-Sylvester Equation<br />

1 ⎡ε<br />

/ D 5.02 ⎛ε<br />

/ D 13 ⎞⎤<br />

=−4.0 log10 ⎢ − log10<br />

⎜ + ⎟<br />

f<br />

3.7 Re 3.7 Re<br />

⎥<br />

⎣<br />

⎝ ⎠⎦<br />

Non-Circular Conduits<br />

Not all flow conduits are circular pipes. An example of a non-circular cross-section in heat<br />

exchanger applications is an annulus, which is the region between two circular pipes. Another is<br />

a rectangular duct, used in HVAC (Heating, Ventilation, and Air-Conditioning) applications.<br />

Less common are ducts of triangular or elliptical cross-sections, but they are used on occasion.<br />

In all these cases, when the flow is turbulent, we use the same friction factor correlations that are<br />

used for circular pipes, substituting an equivalent diameter for the pipe diameter. The equivalent<br />

diameter D , which is set equal to four times the “Hydraulic Radius,” R is defined as follows.<br />

e<br />

h<br />

D<br />

e<br />

Cross -Sectional Area<br />

= 4Rh<br />

= 4×<br />

Wetted Perimeter<br />

In this definition, the term “wetted perimeter” is used to designate the perimeter of the crosssection<br />

that is in contact with the flowing fluid. This applies to a liquid that occupies part of a<br />

conduit, as in sewer lines carrying waste-water, or a creek or river. If a gas flows through a<br />

conduit, the entire perimeter is “wetted.”<br />

Using the above definition, we arrive at the following results for the equivalent diameter for two<br />

common cross-sections. We assume that the entire perimeter is “wetted.”<br />

Rectangular Duct<br />

b<br />

a<br />

For the duct shown in the sketch, the cross-sectional area is ab , while the perimeter is 2( a+<br />

b)<br />

so that the equivalent diameter is written as follows.<br />

2

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