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Chapter 5 Discrete Distributions

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110 CHAPTER 5. DISCRETE DISTRIBUTIONS<br />

> F = cumsum(f)<br />

> F<br />

[1] 0.125 0.500 0.875 1.000<br />

As easy as this is, it is even easier to do with the distrEx package [74]. We define a<br />

random variable X as an object, then compute things from the object such as mean, variance,<br />

and standard deviation with the functions E, var, andsd:<br />

> library(distrEx)<br />

> X E(X); var(X); sd(X)<br />

[1] 1.5<br />

[1] 0.75<br />

[1] 0.8660254<br />

5.2 The <strong>Discrete</strong> Uniform Distribution<br />

We have seen the basic building blocks of discrete distributions and we now study particular<br />

models that statisticians often encounter in the field. Perhaps the most fundamental of all is the<br />

discrete uniform distribution.<br />

ArandomvariableX with the discrete uniform distribution on the integers 1, 2,...,m has<br />

PMF<br />

f X (x) = 1 , x = 1, 2,...,m. (5.2.1)<br />

m<br />

We write X ∼ disunif(m). A random experiment where this distribution occurs is the choice<br />

of an integer at random between 1 and 100, inclusive. Let X be the number chosen. Then<br />

X ∼ disunif(m = 100) and<br />

IP(X = x) = 1<br />

100 , x = 1,...,100.<br />

We find a direct formula for the mean of X ∼ disunif(m):<br />

m∑<br />

m∑<br />

µ = xf X (x) = x · 1<br />

m = 1 m + 1<br />

(1 + 2 + ···+ m) =<br />

m 2 , (5.2.2)<br />

x=1<br />

x=1<br />

where we have used the famous identity 1 + 2 + ···+ m = m(m + 1)/2. That is, if we repeatedly<br />

choose integers at random from 1 to m then, on the average, we expect to get (m + 1)/2. To get<br />

the variance we first calculate<br />

and finally,<br />

IE X 2 = 1 m<br />

m∑<br />

x=1<br />

σ 2 = IE X 2 − (IE X) 2 =<br />

x 2 = 1 m(m + 1)(2m + 3)<br />

=<br />

m 6<br />

(m + 1)(2m + 1)<br />

6<br />

( m + 1<br />

−<br />

2<br />

(m + 1)(2m + 1)<br />

,<br />

6<br />

) 2<br />

= ···= m2 − 1<br />

12 . (5.2.3)<br />

Example 5.4. Roll a die and let X be the upward face showing. Then m = 6, µ = 7/2 = 3.5,<br />

and σ 2 = (6 2 − 1)/12 = 35/12.

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