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P-V & T-s diagrams for ideal Diesel cycle"<br />

Work is done during both 4 → 5 AND 3 → 4 (const. P combustion,<br />

volume increasing, thus w 3→4 = P 3 (v 4 - v 3 )<br />

Ambient intake pressure case shown (no pumping loop)<br />

Pressure (atm)<br />

5.0<br />

4.5<br />

4.0<br />

3.5<br />

3.0<br />

2.5<br />

2.0<br />

1.5<br />

1.0<br />

0.5<br />

Compression Combustion Expansion<br />

Blowdown Intake Exhaust<br />

Intake start 1 2<br />

3 4 5<br />

6 7<br />

P-V diagram<br />

0.0<br />

0.E+00 1.E-04 2.E-04 3.E-04 4.E-04 5.E-04 6.E-04<br />

Cylinder volume (m^3)<br />

Temperature (K)<br />

Compression Combustion Expansion<br />

Blowdown Intake Exhaust<br />

Close T-s cycle 1 2<br />

3 4 5<br />

6 7<br />

1000<br />

900 T-s diagram<br />

800<br />

700<br />

600<br />

500<br />

400<br />

300<br />

200<br />

100<br />

0<br />

-200 0 200 400 600 800<br />

Entropy (J/kg-K)<br />

<strong>AME</strong> <strong>436</strong> - Lecture 8 - Spring 2013 - Ideal cycle analysis<br />

25<br />

Diesel cycle analysis"<br />

Thermal efficiency (ideal cycle, no throttling or friction loss)<br />

work out + work in<br />

" th<br />

= = C (T # T ) + P (v # v ) + C (T # T )<br />

v 4 5 4 4 3 v 2 3<br />

heat in<br />

C P<br />

(T 4<br />

# T 3<br />

)<br />

= (T 4 # T 5 ) + (R /C v )(T 4 # T 3 ) # (T 3 # T 2 )<br />

(C P<br />

/C v<br />

)(T 4<br />

# T 3<br />

)<br />

=1# 1 $ + T 4 (1# (V 5 /V 4 )#($ #1) ) # T 3<br />

(1# (V 2<br />

/V 3<br />

) #($ #1) )<br />

$(T 4<br />

# T 3<br />

)<br />

=1# 1 $ + 1 $ + T 4 (#(V 5 /V 4 )#($ #1) ) + T 3<br />

((V 2<br />

/V 3<br />

) #($ #1) )<br />

$(T 4<br />

# T 3<br />

)<br />

=1+ #T 4<br />

([(V 5<br />

/V 3<br />

)(V 3<br />

/V 4<br />

)] #($ #1) ) + T 3<br />

((V 2<br />

/V 3<br />

) #($ #1) )<br />

$(T 4<br />

# T 3<br />

)<br />

=1+ #T 4<br />

([r /%] #($ #1) ) + T 3<br />

(r #($ #1) )<br />

$(T 4<br />

# T 3<br />

)<br />

= $ #1 + T (1# T /T ) # T (1# T /T )<br />

4 5 4 3 2 3<br />

$<br />

$(T 4<br />

# T 3<br />

)<br />

=1+ #%T 3([r /%] #($ #1) ) + T 3<br />

(r #($ #1) )<br />

$(%T 3<br />

# T 3<br />

)<br />

=1# %([r /%]#($ #1) ) # (r #($ #1) )<br />

=1# 1 % $ #1<br />

$(% #1)<br />

r $ #1 $(% #1)<br />

<strong>AME</strong> <strong>436</strong> - Lecture 8 - Spring 2013 - Ideal cycle analysis<br />

26<br />

!<br />

• 13

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