Quadratics - the Australian Mathematical Sciences Institute
Quadratics - the Australian Mathematical Sciences Institute
Quadratics - the Australian Mathematical Sciences Institute
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{32} • <strong>Quadratics</strong><br />
reflected ray<br />
normal<br />
light ray<br />
0<br />
Note that this implies that <strong>the</strong> angle between <strong>the</strong> ray and <strong>the</strong> tangent is also preserved<br />
after reflection, which is a more convenient idea for us here.<br />
Let P(2ap, ap 2 ) be a point on <strong>the</strong> parabola x 2 = 4ay with focus at S and let T be <strong>the</strong> point<br />
where <strong>the</strong> tangent at P cuts <strong>the</strong> y-axis.<br />
Suppose PQ is a ray parallel to <strong>the</strong> y-axis. Our aim is to show that <strong>the</strong> line PS will satisfy<br />
<strong>the</strong> reflection property, that is, ∠QPB is equal to ∠SPT .<br />
x2 = 4ay<br />
y<br />
Q<br />
B<br />
P(2ap‚ap2)<br />
S(0,a)<br />
x<br />
tangent at P<br />
(0,–ap2)<br />
T<br />
Notice that, since QP is parallel to ST , ∠QPB is equal to ∠ST P, so we will show that<br />
∠ST P = ∠SPT .<br />
Now S has coordinates (0, a), and T has coordinates (0,−ap 2 ), obtained by putting x = 0<br />
in <strong>the</strong> equation of <strong>the</strong> tangent at P. Hence<br />
SP 2 = (2ap − 0) 2 + (ap 2 − a) 2 = a 2 (p 2 + 1) 2