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Quadratics - the Australian Mathematical Sciences Institute

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A guide for teachers – Years 11 and 12 • {39}<br />

Answers to exercises<br />

Exercise 1<br />

a<br />

y<br />

b<br />

y<br />

–3<br />

x<br />

(–3, –4)<br />

–4<br />

3<br />

4<br />

1<br />

– 2<br />

0<br />

x<br />

Exercise 2<br />

The arms of <strong>the</strong> parabola y = x 2 are steeper.<br />

y<br />

y = x2<br />

y =<br />

1<br />

2 x2<br />

x<br />

Exercise 3<br />

y = 2(x − 1) 2 + 3<br />

Exercise 4<br />

The discriminant is 36k 2 − 16(4k + 1) and we set this equal to zero in order to obtain one<br />

real solution to <strong>the</strong> given equation. This gives 9k 2 −16k −4 = 0, which has solutions k = 2<br />

or k = − 2 9 .

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