PDF Viewing archiving 300 dpi - NHV.nu
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APPENDIX I<br />
ERRORS DUE TO THE "RANDOM CHARACTER OF RAIN"<br />
When the precipitation depth, h, is measured with a rain gauge, a <strong>nu</strong>mber of raindrops,<br />
N, with different diameters is caught during a certain time, T.<br />
If we were able to repeat the experiment, it would be expected that we would not find<br />
the same <strong>nu</strong>mber of drops and the same dropsize distribution. This indefiniteness in both<br />
the <strong>nu</strong>mber of drops and the size distribution springs from the random nature of the rainproducing<br />
process.<br />
We can write:<br />
where g3 is the average value of the third power of the dropdiameters, and 0 is the area<br />
of the orifice of the rain gauge. If we could repeat the measurement of h many times, we<br />
would get the average value of h, N and E3, denoted by respectively h, fl and E3.<br />
Our problem is to find the random fluctuations of h, N and E3 round their means.<br />
A measure for these functions is the standard deviation a defined by:<br />
- -<br />
a2(x) = (x - j~)2 = x2 - ~2<br />
-<br />
First, we remark that it is reasonable to assume that the random fluctuations of N and<br />
D3 are independent, so we can write for small a (N) and o (E3):<br />
Further, we note that the standard deviation of the mean of P samples of a stochastic<br />
variable is equal to the standard deviation of the variable itself, divided by t/~. SO we can<br />
estimate a(E3) with<br />
This results into:<br />
3 2 1 3 -- I<br />
( E m N<br />
The problem to determine a (N) remains. We, therefore, divide the time interval, T,<br />
into M equal time intervals, where M >> N. If it is assumed that two raindrops never