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Chapter 8 Scattering Theory - Particle Physics Group

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CHAPTER 8. SCATTERING THEORY 154<br />

the first Born approximation of the scattering amplitude can be written as the Fourier transform<br />

f B = − 1 ∫<br />

e i⃗q·⃗x U(⃗x)d⃗x (8.134)<br />

4π<br />

of the potential. For elastic scattering with k = k ′ and ⃗ k · ⃗k ′ = k 2 cos θ we find<br />

q = 2k sin θ 2 , (8.135)<br />

with θ being the scattering angle. For a central potential it is now useful to introduce polar<br />

coordinates with angles (α,β) such that ⃗q is the polar axis. We thus find that<br />

f B (q) = − 1<br />

4π<br />

= − 1 2<br />

= − 1 q<br />

∫ ∞<br />

0<br />

∫ ∞<br />

0<br />

∫ ∞<br />

0<br />

drr 2 U(r)<br />

drr 2 U(r)<br />

∫ π<br />

0<br />

∫ +1<br />

−1<br />

dα sin α<br />

∫ 2π<br />

0<br />

iqr cos α<br />

d(cos α)e<br />

iqr cos α<br />

dβe<br />

r sin(qr)U(r)dr (8.136)<br />

only depends on q(k,θ). The total cross-section in the first Born approximation hence becomes<br />

∫ π<br />

σtot(k) B = 2π |f B (q)| 2 sin θdθ = 2π ∫ 2k<br />

|f B (q)| 2 qdq (8.137)<br />

0<br />

k 2 0<br />

where we used the differential dq = k cos θ 2 dθ of (8.135) and sinθ dθ = 2 sin θ 2 cos θ 2 dθ = q k<br />

dq<br />

k .<br />

8.4.1 Application: Coulomb scattering and the Yukawa potential<br />

Since the Coulomb potential has infinite range we apply the Born approximation to the Yukawa<br />

potential<br />

U(r) = C e−αr<br />

= C e−r/a<br />

with a = α −1 , (8.138)<br />

r r<br />

which can be regarded as a screened Colomb potential. At the end of the calculation we can<br />

then try to send the screening length a → ∞. For the Born approximation (8.136) we obtain<br />

f B = − 1 q<br />

∫ ∞<br />

0<br />

r sin(qr) C r e−αr dr = − C ∫ ∞<br />

q Im e iqr−αr dr = − C q Im 1<br />

α − iq = − C (8.139)<br />

α 2 + q 2<br />

and the corresponding differential cross section<br />

of the Yukawa potential.<br />

0<br />

dσ B<br />

dΩ = C 2<br />

(α 2 + q 2 ) 2 (8.140)<br />

The Coulomb potential. The electrostatic force between charges Q A and Q B corresponds<br />

to the potential<br />

V Coulomb (r) = Q AQ B 1<br />

4πε 0 r<br />

(8.141)

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