Chapter 15 – Chemical Equilibrium
Chapter 15 – Chemical Equilibrium
Chapter 15 – Chemical Equilibrium
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8<br />
K eq ′ =<br />
+ -<br />
[Ag ][Cl ]<br />
constant<br />
K eq = K eq ′(constant) = [Ag + ][Cl - ] = 1.8 x 10 - 10<br />
This means that if AgCl is placed in a sealed container, the [Ag + ] and [Cl - ] are the<br />
same whether an ounce or pound of AgCl is present. All that is required is that some<br />
be present.<br />
This can be illustrated using a process with which you are familiar. Imagine an empty<br />
swimming pool on a dry, hot summer day. If you put a drop of water into the pool and covered<br />
it, the drop would completely evaporate. In this situation, the system would not be at<br />
equilibrium. Now imagine opening the cover, filling the pool with an inch of water, then<br />
recovering it. At this point some water would remain behind after evaporation. This is a<br />
physical equilibrium. After this point, adding water will NOT result in more water vapor. A<br />
chemical equilibrium works exactly the same way. If some silver(I) chloride is put in a sealed<br />
container and all of it dissolves, no equilibrium exists. If you add more silver(I) chloride and<br />
some is left after stirring, adding more won’t change the amount of silver or chloride ions in the<br />
container.<br />
The same is true for pure liquids too. An important generalization is that for any<br />
heterogeneous equilibrium involving gases; only the gases appear in the equilibrium expression.<br />
Again, while the amounts of pure solids and liquids present are not important, they must be there<br />
for the equilibrium to occur.<br />
<strong>15</strong>.4 Calculating <strong>Equilibrium</strong> Constants<br />
This section is basically a few problems to show you the types of calculations that can be done.