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Serviceability limit state - Eurocodes

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Redistribution of sectional forces due to tension<br />

stiffening<br />

G. Hanswille<br />

Univ.-Prof. Dr.-Ing.<br />

Institute for Steel and<br />

Composite Structures<br />

University of Wuppertal-Germany<br />

fully cracked section<br />

tension stiffening<br />

z 2 =z st<br />

-z st,s<br />

z st,a<br />

a<br />

N s,2<br />

-M s,2<br />

ΔN ts<br />

-M a,2<br />

+ =<br />

ΔN ts<br />

a<br />

-M s<br />

N s<br />

-M a<br />

-M Ed<br />

-N a,2 -ΔN ts<br />

-N a<br />

N s<br />

α<br />

N sε<br />

st<br />

A<br />

=<br />

A<br />

N s<br />

st<br />

a<br />

J<br />

J<br />

st<br />

a<br />

ΔN<br />

ts<br />

= β<br />

ΔN ts<br />

N s,2<br />

M Ed<br />

f<br />

ct,eff<br />

ρ<br />

M<br />

s<br />

α<br />

A<br />

st<br />

s<br />

N<br />

Sectional forces:<br />

N<br />

a<br />

s<br />

= N<br />

M = M<br />

M<br />

s<br />

= N<br />

a<br />

a2<br />

s2<br />

= M<br />

Ed<br />

+ ΔN<br />

− ΔN<br />

a2<br />

J<br />

J<br />

s<br />

st<br />

ts<br />

ts<br />

+ ΔN<br />

= M<br />

= M<br />

ts<br />

a<br />

Ed<br />

Ed<br />

A<br />

A<br />

a<br />

= M<br />

s<br />

J<br />

J<br />

z<br />

Ed<br />

st<br />

z<br />

st<br />

st,s<br />

st,a<br />

J st = J 2<br />

J<br />

J<br />

a<br />

st<br />

+ ΔN<br />

− ΔN<br />

ts<br />

+ ΔN<br />

ts<br />

ts<br />

a<br />

15

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