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Computability and Logic

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PROBLEMS 269<br />

if it is preceded by ∼. Show that if A implies C, <strong>and</strong> neither ∼A nor C is valid,<br />

then there is another such sentence B such that: (i) A implies B; (ii) B implies<br />

C; (iii) any predicate occurs positively in B only if it occurs positively in both<br />

A <strong>and</strong> C, <strong>and</strong> occurs negatively in B if <strong>and</strong> only if it occurs negatively in both<br />

A <strong>and</strong> C.<br />

20.2 Give an example to show that Lyndon’s theorem does not hold if constants are<br />

present.<br />

20.3 (Kant’s theorem on the indefinability of chirality). For points in the plane, we<br />

say y is between x <strong>and</strong> z if the three points lie on a straight line <strong>and</strong> y is between<br />

x <strong>and</strong> z on that line. We say w <strong>and</strong> x <strong>and</strong> y <strong>and</strong> z are equidistant if the distance<br />

from w to x <strong>and</strong> the distance from y to z are the same. We say x <strong>and</strong> y <strong>and</strong> z form<br />

a right-h<strong>and</strong>ed triple if no two distances between different pairs of them are the<br />

same, <strong>and</strong> traversing the shortest side, then the middle side, then the longest side<br />

of the triangle having them as vertices takes one around the triangle clockwise,<br />

as on the right in Figure 20-1.<br />

Figure 20-1. Right <strong>and</strong> left h<strong>and</strong>ed triangles.<br />

Show that right-h<strong>and</strong>edness cannot be defined in terms of betweenness <strong>and</strong><br />

equidistance. (More formally, consider the language with a three-place predicate<br />

P, a four-place predicate Q, <strong>and</strong> a three-place predicate R; consider the<br />

interpretation whose domain is the set of the points in the plane <strong>and</strong> that assigns<br />

betweenness <strong>and</strong> equidistance <strong>and</strong> right-h<strong>and</strong>edness as the denotations of P <strong>and</strong><br />

Q <strong>and</strong> R; <strong>and</strong> finally consider the theory T whose theorems are all the sentences<br />

of the language that come out true under this interpretation. Show that R is not<br />

definable in terms of P <strong>and</strong> Q in this theory.)

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