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HDL™- 64E - Velodyne Lidar

HDL™- 64E - Velodyne Lidar

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N = [Rotation Factor] * [Sequential Duty Cycle] * [Head Overlap] * [Illumination Duration] /<br />

[T i ]<br />

C 5 = N -0.25<br />

Case a: C 5 = {.0255 * 0.75 * 2 * 10 [s] / 18 [us]} -0.25 = .083<br />

Case b: C 5 = {.0145 * 0.75 * 2 * 10 [s] / 18 [us]} -0.25 = .095<br />

Case c: C 5 = {.0059 * 0.75 * 2 * 10 [s] / 18 [us]} -0.25 = .119<br />

Case d: C 5 = {31.25 [kHz] * 1 * 1 * 0.75 *.0004 * 10[s]} -0.25 = .321<br />

The limits are then calculated by:<br />

AEL train, SP = AEL SP * C 5 = 514 nJ<br />

AEL train, SP = AEL 18us * C 5<br />

Class 1M AEL 18us = 7 * 10 -4 * t 0.75 * C 4 (from IEC 60285-1 Table 4)<br />

Where t = 18 us and C4 = 2.57<br />

= 497 nJ<br />

Class 1M<br />

Case a: AEL train, SP 1M = 497 nJ * .083 = 41.3 nJ<br />

Case b: AEL train, SP 1M = 497 nJ * .095 = 47.2 nJ<br />

Case c: AEL train, SP 1M = 497 nJ * .119 = 59.1 nJ<br />

Case d: AEL train, SP 1M = 514 nJ * .321 = 165.0 nJ<br />

Condition 3 Conclusion<br />

Since all Cases are lower than the Class 1M AEL train, SP , the Product is rated as Class 1M for<br />

this Condition.<br />

Condition 3B: Repetitive Pulse Accessible Emission Limit (18 us exposure)<br />

Since there are multiple pulses within an 18 us period, we must also check that the total<br />

energy in the 18 us period does not exceed the AEL for 18us.<br />

Also, since there is no overlap of multiple laser emissions, there is no burst mode operation<br />

in 18 us for Cases d, so this Case will not be evaluated in this calculation.<br />

The maximum number of laser emissions that can occur in an 18 us period is:<br />

Case a: 5<br />

Case b: 5<br />

Case c: 3<br />

So, the total energy in this 18 us period is:<br />

Sub-Case a: 5 * Detected Laser Energy SP = 5 * 32.1 nJ = 160.5 nJ<br />

Sub-Case b: 5 * Detected Laser Energy SP = 5 * 31.6 nJ = 158.0 nJ<br />

Sub-Case b: 5 * Detected Laser Energy SP = 3 * 22.7 nJ = 68.1 nJ<br />

Class 1M AEL 18us = 7 * 10 -4 * t 0.75 * C 4 (from IEC 60285-1 Table 4)<br />

Where t = 18 us and C4 = 2.57<br />

= 497 nJ<br />

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