HDLâ¢- 64E - Velodyne Lidar
HDLâ¢- 64E - Velodyne Lidar
HDLâ¢- 64E - Velodyne Lidar
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N = [Rotation Factor] * [Sequential Duty Cycle] * [Head Overlap] * [Illumination Duration] /<br />
[T i ]<br />
C 5 = N -0.25<br />
Case a: C 5 = {.0255 * 0.75 * 2 * 10 [s] / 18 [us]} -0.25 = .083<br />
Case b: C 5 = {.0145 * 0.75 * 2 * 10 [s] / 18 [us]} -0.25 = .095<br />
Case c: C 5 = {.0059 * 0.75 * 2 * 10 [s] / 18 [us]} -0.25 = .119<br />
Case d: C 5 = {31.25 [kHz] * 1 * 1 * 0.75 *.0004 * 10[s]} -0.25 = .321<br />
The limits are then calculated by:<br />
AEL train, SP = AEL SP * C 5 = 514 nJ<br />
AEL train, SP = AEL 18us * C 5<br />
Class 1M AEL 18us = 7 * 10 -4 * t 0.75 * C 4 (from IEC 60285-1 Table 4)<br />
Where t = 18 us and C4 = 2.57<br />
= 497 nJ<br />
Class 1M<br />
Case a: AEL train, SP 1M = 497 nJ * .083 = 41.3 nJ<br />
Case b: AEL train, SP 1M = 497 nJ * .095 = 47.2 nJ<br />
Case c: AEL train, SP 1M = 497 nJ * .119 = 59.1 nJ<br />
Case d: AEL train, SP 1M = 514 nJ * .321 = 165.0 nJ<br />
Condition 3 Conclusion<br />
Since all Cases are lower than the Class 1M AEL train, SP , the Product is rated as Class 1M for<br />
this Condition.<br />
Condition 3B: Repetitive Pulse Accessible Emission Limit (18 us exposure)<br />
Since there are multiple pulses within an 18 us period, we must also check that the total<br />
energy in the 18 us period does not exceed the AEL for 18us.<br />
Also, since there is no overlap of multiple laser emissions, there is no burst mode operation<br />
in 18 us for Cases d, so this Case will not be evaluated in this calculation.<br />
The maximum number of laser emissions that can occur in an 18 us period is:<br />
Case a: 5<br />
Case b: 5<br />
Case c: 3<br />
So, the total energy in this 18 us period is:<br />
Sub-Case a: 5 * Detected Laser Energy SP = 5 * 32.1 nJ = 160.5 nJ<br />
Sub-Case b: 5 * Detected Laser Energy SP = 5 * 31.6 nJ = 158.0 nJ<br />
Sub-Case b: 5 * Detected Laser Energy SP = 3 * 22.7 nJ = 68.1 nJ<br />
Class 1M AEL 18us = 7 * 10 -4 * t 0.75 * C 4 (from IEC 60285-1 Table 4)<br />
Where t = 18 us and C4 = 2.57<br />
= 497 nJ<br />
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