Bluman A.G. Elementary Statistics- A Step By Step Approach

Instructor’s Section AnswersH 1 : There is an interaction effect between type of formuladelivery system and review organization. Review:H 0 : There is no difference in mean scores based on wholeads the review. H 1 : There is a difference in mean scoresbased on who leads the review. Formulas: H 0 : There is nodifference in mean scores based on who provides theformulas. H 1 : There is a difference in mean scores basedon who provides the formulas.C.V. 4.49; d.f.N. 1; d.f.D. 16; F 5.244 for revieworganization. There is sufficient evidence to conclude adifference in mean scores based on who leads the review.The formula and interaction effects are not significant.ANOVA Summary Table for Exercise 8Source of variation SS d.f. MS F P-valueSample 288.8 1 288.8 5.244 0.036Columns 51.2 1 51.2 0.930 0.349Interaction 5 1 5 0.091 0.767Within 881.2 16 55.075Total 1226.2 199. H 0 : There is no interaction effect between the typeof exercise program and the type of diet on a person’sglucose level. H 1 : There is an interaction effect betweentype of exercise program and the type of diet on aperson’s glucose level.H 0 : There is no difference in the means for the glucoselevels of the people in the two exercise programs.H 1 : There is a difference in the means for the glucoselevels of the people in the two exercise programs.H 0 : There is no difference in the means for the glucoselevels of the people in the two diet programs. H 1 : Thereis a difference in the means for the glucose levels of thepeople in the two diet programs.ANOVA Summary TableSource SS d.f. MS FExercise 816.750 1 816.750 60.50Diet 102.083 1 102.083 7.56Interaction 444.083 1 444.083 32.90Within 108.000 8 13.500Total 1470.916 11At a 0.05, d.f.N. 1, d.f.D. 8, and the critical valueis 5.32 for each F A , F B , and F AB . Hence, all three nullhypotheses are rejected. The cell means should becalculated.DietExercise A BI 64.000 57.667II 68.333 86.333Since the means for exercise program I are both smallerthan those for exercise program II and the verticaldifferences are not the same, the interaction is ordinal.Hence you can say that there is a difference for exerciseand diet, and that an interaction effect is present.Chapter Quiz1. False 2. False3. False 4. True5. d 6. a7. a 8. c9. ANOVA 10. Tukey11. Two12. H 0 : m 1 m 2 m 3 m 4 . H 1 : At least one mean isdifferent from the others (claim). C.V. 3.49; a 0.05;d.f.N. 3; d.f.D. 12; F 3.23; do not reject. There isnot enough evidence to support the claim that there is adifference in the means.13. H 0 : m 1 m 2 m 3 . H 1 : At least one mean is different fromthe others (claim). C.V. 6.93; a 0.01; d.f.N. 2;d.f.D. 12; F 3.49. There is not enough evidence tosupport the claim that at least one mean is different fromthe others. Writers would want to target their material tothe age group of the viewers.14. H 0 : m 1 m 2 m 3 . H 1 : At least one mean differs from theothers (claim). C.V. 4.26; d.f.N. 2; d.f.D. 9;F 10.025; reject. There is enough evidence to concludethat at least one mean differs from the others. Tukey test:C.V. 3.95; X 1 versus X 2, q 1.28; X 1 versus X 3,q 4.74; X 2 versus X 3 , q 6.02. There is a significantdifference between X 1 and X 3 and between X 2 and X 3 .15. H 0 : m 1 m 2 m 3 . H 1 : At least one mean differs from theothers (claim). C.V. 2.92; d.f.N. 2; d.f.D. 8;F 6.652; reject. Scheffé test: C.V. 8.918; X 1 versusX 2 , F s 9.32; X 1 versus X 3 , F s 10.132; X 2 versus X 3 ,F s 0.1258. There is a significant difference betweenX 1 and X 2 and between X 1 and X 3 .16. H 0 : m 1 m 2 m 3 m 4 . H 1 : At least one mean is differentfrom the others (claim). C.V. 3.07; a 0.05;d.f.N. 3; d.f.D. 21; F 0.4564; do not reject. Thereis not enough evidence to support the claim that at leastone mean is different from the others.IS–67