Acquisition Lesson Planning Form - Ciclt.net
Acquisition Lesson Planning Form - Ciclt.net
Acquisition Lesson Planning Form - Ciclt.net
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Circle and Lines2 2( x 20) ( y 20) 253y 20 ( x 20)4Graphic Organizer #1Solving Systems Involving CirclesStep 2: Substitute your equation from step 1 into thecircle equation for y.Step 3: Square the binomials.Step 1: Convert the linear equation to slope – interceptform. (Be careful, this may be done for you.)Step 5: Use the quadratic formula (or any method)to find the two values for x.Step 6: Substitute the values of x into the linearequations (from Step 1) to find the two values for y.Step 4: Combine like terms and write the equation instandard form.Step 7: Write the solution set.Write the values as orderedpairs.
Circle and Circlesxy2 22 02 2x y x8 10 0Graphic Organizer #2Solving Systems Involving CirclesStep 1: Subtract the equations to eliminate the squaredterms. (Make sure the equations are written in generalform.)Step 2: Solve the equation for x or y depending onwhich variable is still there.Step 3: Substitute the answer from step 2 into theequations and solve for the other variable.Step 4: Write the solutions as ordered pairs.
Solve the systems.1) x 2 + y 2 = 16Y = 3 – xGuided Practice WorksheetSolving Systems involving Circles2) x 2 + y 2 = 36Y = 2x + 153) (x+4) 2 + (y – 10) 2 = 25X = 24) (x + 4) 2 + (y + 2) 2 = 254x + 3y = 35) x 2 + y 2 = 28Y = -3x + 16) x 2 + y 2 – 25 = 0X 2 + y 2 + 6x – 7 = 07) x 2 + y 2 – 16 = 0X 2 + y 2 + 2x – 24 = 08) x 2 + y 2 - 9 = 0X 2 + y 2 + 20y + 70 = 09) x 2 + y 2 = 49(x – 6 ) 2 + (y – 2) 2 = 910) (x – 1) 2 + (y + 5 ) 2 = 25(x – 1) 2 + (y – 4) 2 = 16