concrete - filled steel tube columns - tests ... - CCVI Information
concrete - filled steel tube columns - tests ... - CCVI Information
concrete - filled steel tube columns - tests ... - CCVI Information
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NOTATIOND outer diameter of the circular <strong>steel</strong> <strong>tube</strong>h larger dimension of the rectangular <strong>steel</strong> <strong>tube</strong>b smaller dimension of the rectangular <strong>steel</strong> <strong>tube</strong>t thickness of the <strong>steel</strong> <strong>tube</strong>f y yield stress of the <strong>steel</strong>E s modulus of elasticity of the <strong>steel</strong> (E a in EC4) = 200 N/mm 2 if not given by the testerf cyl cylinder strength of the <strong>concrete</strong> = 0.8f cu if cube strength given by the testerf cu cube strength of the <strong>concrete</strong>E c secant modulus of elasticity of the <strong>concrete</strong> to 0.4f cyl= 22*((f cyl + 8)/10)^0.3 if E c was not given by the testerL length of the columne eccentricity of load on the end of the column, causing end momentN uEC4 ultimate load capacity of the column as calculated using Eurocode 4N u axial load at failure in the testχ buckling factor = 1/(φ + √(φ 2 - λ ) ) where φ = 0.5*(1 + 0.21*( λ - 0.2) + λ 2 )λ slenderness ratio = √(N plRk /N cr )N plRk plastic resistance of the composite sectionN cr elastic critical load = π 2 (EI) eff /L 2(EI) eff effective flexural stiffness of the composite section = E a I a + 0.6*E c I ck factor to take account of second order effects in the simplified analysis, which,for <strong>columns</strong> with equal end moment, = 1/(1 – N u /N cr,eff )where N cr,eff uses (EI) eff,II = 0.9*(E a I a + 0.5*E c I c ) to obtain the elastic critical load