- Page 1 and 2: Author (David R. Kohel) /Title (Cry
- Page 4 and 5: CONTENTS1 Introduction to Cryptogra
- Page 6: PrefaceWhen embarking on a project
- Page 10 and 11: information. We introduce here some
- Page 12 and 13: ut strings in A ∗ map injectively
- Page 14 and 15: CHAPTERTWOClassical Cryptography2.1
- Page 16 and 17: LV MJ CW XP QO IG EZ NB YH UA DS RK
- Page 18 and 19: As a special case, consider 2-chara
- Page 20 and 21: Note that if d k = 1, then we omit
- Page 22: ExercisesSubstitution ciphersExerci
- Page 25 and 26: Ciphertext-only AttackThe cryptanal
- Page 27 and 28: of size n, suppose that p i is the
- Page 29 and 30: Note that ZKZ and KZA are substring
- Page 31: Checking possible keys, the partial
- Page 36 and 37: CHAPTERFOURInformation TheoryInform
- Page 38 and 39: For each of these we can extend our
- Page 40 and 41: in terms of the cryptosystem), then
- Page 42 and 43: CHAPTERFIVEBlock CiphersData Encryp
- Page 44 and 45: Deciphering. Suppose we begin with
- Page 46 and 47: The Advanced Encryption Standard al
- Page 48 and 49: 1. Malicious substitution of a ciph
- Page 50 and 51: locks M j−1 , . . . , M 1 as well
- Page 52: where X = K ⊕ M = (X 1 , X 2 , X
- Page 55 and 56: 6.2 Properties of Stream CiphersSyn
- Page 57 and 58: Exercise. Verify that the equality
- Page 59 and 60: n 2 n − 11 12 33 74 155 316 637 1
- Page 61 and 62: Exercise 6.6 In the previous exerci
- Page 63 and 64: Exercise 6.9 Compute the first 8 te
- Page 65 and 66: which holds since −4 = 17 + (−1
- Page 67 and 68: must therefore have a divisor of de
- Page 69 and 70: Shrinking Generator cryptosystemLet
- Page 72 and 73: CHAPTEREIGHTPublic Key Cryptography
- Page 74 and 75: Initial setup:1. Alice and Bob publ
- Page 76 and 77: We apply this rule in the RSA algor
- Page 78 and 79: the discrete logarithm problem (DLP
- Page 80 and 81: Man in the Middle AttackThe man-in-
- Page 82: Exercise 8.6 Fermat’s little theo
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k < p − 1 with GCD(k, p − 1) =
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CHAPTERTENSecret SharingA secret sh
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using any t shares (x 1 , y 1 ), .
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sage-------------------------------
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sage: x.is_unit?Type:builtin_functi
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Python (hence SAGE) has useful data
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sage: n = 12sage: for i in range(n)
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sage: I = [55+i for i in range(3)]
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sage: I = [7, 4, 11, 11, 14, 22, 14
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ExercisesRead over the above SAGE t
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102
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Solution. The block length is the n
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Solution.below.The coincidence inde
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analysis of the each of the decimat
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arbitrary permutation of the alphab
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In order to understand naturally oc
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We do this by first verifying the e
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Solution.None provided.Linear feedb
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Multiplying each through by the con
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Solution. The linear complexity of
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If a, b, and c are as above, then f
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Exercise 8.5 Use SAGE to find a lar
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Solution. Now we can verify that e
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which has no common factors with p
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sage: p = 2^32+61sage: m = (p-1).qu
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sage: a5 := a^n5sage: c5 := c^n5sag
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The application of this function E
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5. (∗) How many elements a of G h
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1. The value f(0) of the polynomial