ECE-320 CH02.pdf - Unix.eng.ua.edu

G. Rizzoni, Principles and Applications of Electrical Engineering Problem solutions, Chapter 2The same voltage appears across both R1and Reqand, therefore, these element are in parallel. Applyingthe voltage divider rule:R1|| Req1000VR= V =1 SR + R || R 3R+ 20The power absorbed by the 20-Ω resistor is:P20Ω=1( V )12eq1 1000 = 20 3R+ 20 250000R1 = =R( 3R+ 20)220R = 10 Ω________________________________________________________________________Solution:Problem 2.41Known quantities:Schematic of the circuit shown in Figure P2.41.Find:The equivalent resistance Reqof the infinite network of resistors.Analysis:We can see the infinite network of resistors as the equivalent to the circuit in the picture:R eqRRRR eqTherefore,ReqRReq= R + ( R || Req) + R = 2R+ R eq= ( 1+ 3)RR + Req________________________________________________________________________2.32