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my forty years on his shoulders - Department of Mathematics

my forty years on his shoulders - Department of Mathematics

my forty years on his shoulders - Department of Mathematics

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19PROV[x 1 /#(A)] → PROV[x 1 /PR(#(A))]is provable in T. By Lemma 4.2,PROV[x 1 /t] → PROV[x 1 /PR(t)]is provable in T. By c<strong>on</strong>diti<strong>on</strong> 10, T provesPR(t) = #(PROV[x 1 /t]).By c<strong>on</strong>diti<strong>on</strong> 8, T provesNEG(#(PROV[x 1 /t])) = #(¬PROV[x 1 /t]) .By Lemma 4.2, T provesNEG(PR(t)) = t.The sec<strong>on</strong>d claim follows immediately. QEDWe let CON be the sentence(∀x 1 )(¬(PROV ∧ PROV[x 1 /NEG(x 1 )])).THEOREM 4.5. (Abstract sec<strong>on</strong>d incompleteness). Let T obey c<strong>on</strong>diti<strong>on</strong>s 1-12.Suppose T proves CON. Then T is inc<strong>on</strong>sistent.Pro<strong>of</strong>: Suppose T is as given. By Lemma 4.4, T provesPROV[x 1 /t] → PROV[x 1 /PR(t)] ∧ PROV[x 1 /NEG(PR(t))].Since T proves CON, T proves¬(PROV[x 1 /PR(t)] ∧ PROV[x 1 /NEG(PR(t))]).Hence T proves ¬PROV[x 1 /t]. By Lemma 4.3, T is inc<strong>on</strong>sistent. QEDInformal statements <strong>of</strong> Gödel's Sec<strong>on</strong>d Incompleteness Theorem aresimple and dramatic. However, current versi<strong>on</strong>s <strong>of</strong> the Formal Sec<strong>on</strong>dIncompleteness are complicated and awkward. Even the abstract form <strong>of</strong> sec<strong>on</strong>d

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