Integration - the Australian Mathematical Sciences Institute
Integration - the Australian Mathematical Sciences Institute
Integration - the Australian Mathematical Sciences Institute
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{20} • <strong>Integration</strong>Exercise 8Find∫(3x 2 + 3 x) d x.Exercise 9Prove <strong>the</strong> <strong>the</strong>orem above (linearity of integration) using similar rules for differentiation.Calculating areas with antiderivativesA general method to find <strong>the</strong> area under a graph y = f (x) between x = a and x = b isgiven by <strong>the</strong> following important <strong>the</strong>orem.Theorem (Fundamental <strong>the</strong>orem of calculus)Let f (x) be a continuous real-valued function on <strong>the</strong> interval [a,b]. Then∫ ba[ bf (x) d x = F (x)]= F (b) − F (a),awhere F (x) is any antiderivative of f (x).The notation [ F (x) ] bais just a shorthand to substitute x = a and x = b into F (x) andsubtract; it is synonymous with F (b) − F (a).Note that any antiderivative of f (x) will work in <strong>the</strong> above <strong>the</strong>orem. Indeed, if we havetwo different antiderivatives F (x) and G(x) of f (x), <strong>the</strong>n <strong>the</strong>y must differ by a constant,so G(x) = F (x)+c for some constant c. Then we have to get <strong>the</strong> same answer whe<strong>the</strong>r weuse F or G, sinceG(b) −G(a) = ( F (b) + c ) − ( F (a) + c )= F (b) − F (a).We give a proof of <strong>the</strong> <strong>the</strong>orem, assuming our previous statements:• <strong>the</strong> derivative of <strong>the</strong> area function is f (x)• any two antiderivatives of f (x) differ by a constant.