12.07.2015 Views

Stat 5101 Lecture Notes - School of Statistics

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3.4. JOINT, CONDITIONAL, AND MARGINAL 101to evaluate the integrals. HenceSimilarly∫ ∞0f(x | y) =f(x, y)∫f(x, y) dx= x + y21+y 2e−x∫ ∞∫ ∞h(x, y) dy = xe −x e −y dy + e −x y 2 e −y dy0=(x+2)e −xAgain, we used (3.23) to evaluate the integrals. S<strong>of</strong>(y | x) =f(x, y)∫f(x, y) dy= x + y2x +2 e−yThings become considerably more complicated when the support <strong>of</strong> the jointdensity is not a rectangle with sides parallel to the axes. Then the domains <strong>of</strong>integration depend on the values <strong>of</strong> the conditioning variable.Example 3.4.4 (A Density with Weird Support).Consider the function{x+y 2 , x > 0,y>0,x+y0and y>0 and x + y

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