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Stat 5101 Lecture Notes - School of Statistics

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4.4. THE POISSON PROCESS 119Hence the Jacobian isJ(u, v) =∣∂x∂u∂y∂u∂x∂v∂y∂v∣ ∣∣∣∣∣ ∣ = v u1−v −u∣ = −uThe joint density <strong>of</strong> X and Y is f X (x)f Y (y) by independence. By the change<strong>of</strong> variable formula, the joint density <strong>of</strong> U and V isf U,V (u, v) =f X,Y [uv, u(1 − v)]|J(u, v)|= f X (uv)f Y [u(1 − v)]u= λsλtΓ(s) (uv)s−1 e −λuvΓ(t) [u(1 − v)]t−1 e −λu(1−v) u= λs+tΓ(s)Γ(t) us+t−1 e −λu v s−1 (1 − v) t−1Since the joint density factors into a function <strong>of</strong> u times a function <strong>of</strong> v, thevariables U and V are independent. Since these functions are proportional tothe gamma and beta densities asserted by the theorem, U and V must actuallyhave these distributions.Corollary 4.3.B(s, t) = Γ(s)Γ(t)Γ(s + t)Pro<strong>of</strong>. The constant in the joint density found in the pro<strong>of</strong> <strong>of</strong> the theorem mustbe the product <strong>of</strong> the constants for the beta and gamma densities. Henceλ s+tΓ(s)Γ(t) =Solving for B(s, t) gives the corollary.λs+t 1Γ(s + t) B(s, t)For moments <strong>of</strong> the beta distribution, see Lindgren pp. 176–177.4.4 The Poisson Process4.4.1 Spatial Point ProcessesA spatial point process is a random pattern <strong>of</strong> points in a region <strong>of</strong> space.The space can be any dimension.A point process is simple if it never has points on top <strong>of</strong> each other so thateach point <strong>of</strong> the process is at a different location in space. A point process isboundedly finite if with probability one it has only a finite number <strong>of</strong> points inany bounded set.Let N A denote the number <strong>of</strong> points in a region A. Since the point patternis random, N A is a random variable. Since it counts points, N A is a discrete

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