30~chapter 01 intro.pdf

1.4Four patterns are enough to exhaustively test each gate in the parity checker independent of n.They are as follows.(00┅0), (11┅1),(011┅1), and (100┅0).1.5λk= ∑ λi, ii=11000λ =910 . Thus, λ = −6 −410 × 500 = 5×101MTBF =λ = 32× 10 = 2000 hours.1.6t = T × (1 − System _ availability)= 1× 365× 24× 60× 60 × (1 − 99.999%) = 315.36sec1.7Defect level =(1−0.9)1− 0.5 = 1− 0.933 = 6.7%VLSI Test Principles and Architectures Ch. 1 – Introduction – P. 2/2