Name of the Module PIE CHARTS & LINE GRAPHS - Sreenivasa ...

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REASONING COURSEPie Charts & Line GraphsFrom (i) and (ii), we get:3x x 100E 1 165 3 x 150 15 = = = (Required ratio).E 24x x 100 4 x 165 2215042. Answer: (B)Profit percent of Company Y in 1997 = 35.Let the income of Company Y in 1997 be Rs. x crores.Then, 35 = x - 220 x 100 x = 297.220Income of Company Y in 1997 = Rs. 297 crores.43. Answer: (D)Let the expenditures of each companies X and Y in 1996 be Rs. x crores.And let the income of Company X in 1996 be Rs. z crores.So that the income of Company Y in 1996 = Rs. (342 - z) crores.Then, for Company X we have:40 = z - x 40 z 100zx 100= - 1 x = .... (i)x 100 x 140Also, for Company Y we have:45 = (342 - z) 45 (342 - z) (342 - z) x 100x 100 = - 1 x = .... (ii)x 100 x 145From (i) and (ii), we get:100z (342 - z) x 100= z = 168.140 145Substituting z = 168 in (i), we get : x = 120.Total expenditure of Companies X and Y in 1996 = 2x = Rs. 240 crores.Total income of Companies X and Y in 1996 = Rs. 342 crores.Total profit = Rs. (342 - 240) crores = Rs. 102 crores.44. Answer: (A)Let the income of Company X in 1998 be Rs. x crores.Then, 55 = x - 200 x 100 x = 310.200Expenditure of Company X in 2001 = Income of Company X in 1998= Rs. 310 crores.Let the income of Company X in 2001 be Rs. z crores.Then, 50 = z - 310 x 100 z = 465.310Income of Company X in 2001 = Rs. 465 crores.45. Answer: (D)Let the incomes of each of the two Companies X and Y in 1999 be Rs. x.And let the expenditures of Companies X and Y in 1999 be E 1 and E 2 respectively.Then, for Company X we have:50 = x - E 1 50 xx 100 = - 1 x = 150 E 1 .... (i)E 1 100 E 1 100SITAMS Page 24
REASONING COURSEPie Charts & Line GraphsAlso, for Company Y we have:60 = x - E 2 60 xx 100 = - 1 x = 160 E 2 .... (ii)E 2 100 E 2 10046. Answer: (B)The differences between the percentages of candidates qualified to appeared for the give pairsof years are:For 1994 and 1995 = 50 - 30 = 20.For 1998 and 1999 = 80 - 80 = 0.For 1994 and 1997 = 50 - 30 = 20.For 1997 and 1998 = 80 - 50 = 30.For 1999 and 2000 = 80 - 60 = 20.Thus, the maximum difference is between the years 1997 and 1998.47. Answer: (D)The graph gives the data for the percentage of candidates qualified to appeared and unless theabsolute values of number of candidates qualified or candidates appeared is know we cannotcompare the absolute values for any two years.Hence, the data is inadequate to solve this question.48. Answer: (C)The number of candidates appeared in 1998 be x.Then, 80% of x = 21200 x = 21200 x 100 = 26500 (required number).8049. Answer: (D)The total number of candidates qualified in 1996 and 1997 together, cannot be determineduntil we know at least, the number of candidates appeared in any one of the two years 1996or 1997 or the percentage of candidates qualified to appeared in 1996 and 1997 together.Hence, the data is inadequate.50. Answer: (C)The number of candidates qualified in 1999 = (80% of 26500) = 21200.Number of candidates qualified in 2000 = ( 33500 - 21200 ) = 12300.Let the number of candidates appeared in 2000 be x.Then, 60% of x = 12300 x = 12300 x 100 = 20500.60SITAMS Page 25
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