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Standard range - Belting Ware

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30<br />

Calculation<br />

optibelt OMEGA HL/HP and optibelt OMEGA<br />

Belt tension<br />

Belt tension for Optibelt OMEGA HP/Optibelt<br />

OMEGA HL and Optibelt OMEGA timing belts<br />

For faultless power transmission and for the achievement of<br />

acceptable belt service life, the correct belt tension is of the utmost<br />

importance. Too low or too high a belt tension will lead to the<br />

premature failure of the timing belts. Over tensioning often leads<br />

to bearing failure on the prime mover or the driven machine.<br />

Experience showed that unscientific belt tensioning methods, such<br />

as the “thumb pressure method”, are not suitable for applying the<br />

optimum tension to the drive for maximum efficiency and drive/<br />

bearing life. It is therefore recommended that the correct static belt<br />

tension should be calculated for each drive.<br />

By virtue of their extremely low stretch characteristics Optibelt<br />

timing belts do not require any further tensioning after correct<br />

installation if properly used.<br />

Symbol<br />

F = test force [N]<br />

Sa = static shaft loading [N]<br />

Sn3 = circumferential force to be effectively transmitted [N]<br />

Ea = belt deflection for given span length [mm]<br />

L = span length [mm]<br />

1. Calculation of the test force F<br />

F =<br />

S n3<br />

20<br />

P · 1000<br />

Sn3 = v =<br />

v<br />

2. Calculation of the belt deflection E a for the existing<br />

span length L<br />

L<br />

Ea =<br />

50<br />

L = a nom 2 –<br />

3. Calculation of the minimum static shaft loading<br />

S a = S n3 · 1.1<br />

dwg – dwk ( )<br />

2<br />

4. Calculation of the frequency for measuring the belt tension<br />

using the Optibelt frequency tension tester<br />

T<br />

f =<br />

4 · k · L<br />

T = 0.5 · Sa k belt weight in kg/m from Table 8, page 43<br />

L span length in mm<br />

2<br />

2<br />

d wk · n k<br />

19100<br />

Apply test force F in the centre of the span perpendicular to the belt<br />

top surface as shown in the illustration below; measure the<br />

deflection E a, correct the tension if necessary and re-check.<br />

1352<br />

F = = 67.60 N<br />

20<br />

18.5 · 1000<br />

Sn3 =<br />

13.68<br />

91.67 · 2850<br />

v =<br />

19100<br />

Sn3 = 1352 N v = 13.68 m/s<br />

Ea = = 8.3 mm<br />

L =<br />

142.60 – 91.67<br />

415.22 ( ) 2<br />

2 414.44<br />

50<br />

2<br />

–<br />

= 414.44 mm<br />

S a = 1352 N · 1.1 = 1487.2 N<br />

743.6<br />

f = = 78.9 Hz<br />

4 · 0.174 · 0.414<br />

T = 0.5 · 1487.2 N = 743.6 N<br />

k = 0.174 kg/m<br />

L = 0.414 m<br />

2

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