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Application –PEEC Resultszbl 1ay0El 3l 22 2Z X2 2 2f( XYZ , , ) = (( − ) Xln( Y+ X + Y + Z )2 62 2Z Y 2 2 2 2 2 2+ ( − ) Y ln( X + X + Y + Z ) + XYZ ln( Z + X + Y + Z )ρ2 62 2X Z YZ Y Z XZx− arctan− arctan22 2 222 2 2X X + Y + Z Y X + Y + Z3Z XY XY 2 2 2arctanX Y Z2 2 2− − + +6 Z X + Y + Z 3Bar-filament formulation and its Equation2.512.52.492.48voltage,V2.472.462.452.442.43PEEC(Lp,R,C)HFSSCSTBasic PEEC model without dipole2.42100 200 300 400 500 600 700 800 900 1000Frequency,MHzComparison between HFSS,CST and PEEC71