Plant layout

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Example 5.1 (solution)Iteration No.1To: 1 2 3 4 “From” SumsFrom: 1 0 5 0 25 302 30 0 0 15 453 10 40 0 0 504 10 0 0 0 10“To” Sums 50 45 0* 40 135* The minimum sum value is the “To” sum for machine 3.Machine sequence:314
Example 5.1 (solution)Iteration No.2To: 1 2 4 “From” SumsFrom: 1 0 5 25 302 30 0 15 454 10 0 0 10“To” Sums 40 5* 40 85* The minimum sum value is the “To” sum for machine 2.Machine sequence:3 215
Page 3 and 4: Some of the objectives of the plant
Page 5 and 6: From - to chart• Provides informa
Page 8 and 9: Machine Sequencing• Machining cen
Page 10 and 11: Hollier Method 1Step 3:Assign machi
Page 12 and 13: Hollier Method 1Step 4:Reformat the
Page 16 and 17: Example 5.1 (solution)Iteration No.
Page 18 and 19: Percentage of in-sequence moves(%)
Page 20 and 21: Activity relationship analysis• A
Page 22 and 23: Proportion of each ratingRatingA &
Page 24 and 25: Layout algorithms• In general, la
Page 26 and 27: Relationship Diagramming Process (R
Page 28 and 29: Relationship Diagramming Process (R
Page 30 and 31: Example 5.2Given the activity relat
Page 32 and 33: Example 5.2 (solution) 1 st stageNe
Page 34 and 35: Example 5.2 (solution) 1 st stageWi
Page 36 and 37: Example 5.2 (solution) 2 nd stageFu
Page 38 and 39: Example 5.2 (solution) 2 nd stage12
Page 40 and 41: Example 5.2 (solution) 2 nd stage14
Page 42 and 43: CRAFT-(Computerized RelativeAllocat
Page 44 and 45: Example (Craft)Initial layoutTotal
Page 46 and 47: AB interchangingMovement Cost = (20
Page 48 and 49: Other interchanges and savingsADSav
Page 50: Interchanges and savingsADBCSavings

Plant layout

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