ZBIRKA POTPUNO RIJEŠENIH ZADATAKA

Rješenja i kompletni postupak
M-8-Kvadriranje i korjenovanje
4.
Koristimo sve što smo naučili u prva tri zadatka:
2 2
( ) ( ) ( ) ( )
10) − − 0.5 =− 0.5 =− 0.5⋅ 0.5 =− 0.25 =−0.25
↓
u ovom tipu zadataka raditi ćemo samo po
−
( a)
2 2
( ) ( )
2 2
− = a
II načinu po pravilu: u ovom zadatku:
( ) ( )
− − 0.5 = − 0.5 = − 0.5⋅ 0.5 = −( 0.25)
=−0.25
minus ispred zagrade ostaje do zadnjeg koraka kada konačnom rješenju daje negativan predznak
2 2 2
( ) ( ) ( )
( −1) ⋅( )
ili minus ispred zagrade možemo pisati i kao: zagrada
( ) ( )
− 0.5 =−1⋅ − 0.5 =−1⋅ 0.5 =−1⋅ 0.5⋅ 0.5 =−1⋅ 0.25 =−0.
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ili
2 2
( ) ( ) ( ) ( )
2 2
−( − ) =− ( ) =−
11) − − 0.04 =− 0.04 =− 0.04⋅ 0.04 =− 0.0016 =−0.0016
ili nešto kraći postupak:
0.04 0.04 0.0016
drugi i treći korak napravili smo "u glavi"
2 2 2
( ) ( ) ( ) ( )
− − 0.04 = −1⋅ − 0.04 = −1⋅ 0.04 = −1⋅ 0.04⋅ 0.04 = −1⋅ 0.0016 = −0.0016
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ili
ili
2 2
( ) ( ) ( ) ( )
− −0.12 =− 0.12 =− 0.12⋅ 0.12 =− 0.144 =−0.0144
2 2 2
( ) ( ) ( ) ( )
− − 0.12 = −1⋅ − 0.12 = −1⋅ 0.12 = −1⋅ 0.12⋅ 0.12 = −1⋅ 0.144 = −0.0144
2 2
( ) ( ) ( ) ( )
13) − − 1.1 =− 1.1 =− 1.1⋅ 1.1 =− 1.21 =−1.21
2 2 2
( ) ( ) ( ) ( )
− − 1.1 = −1⋅ − 1.1 = −1⋅ 1.1 = −1⋅ 1.11.1 ⋅ = −11.21 ⋅ = −1.21
2 2
( ) ( )
14) 2.5 2.5
ili
ili
− − = − = ( ) ( )
− 2.5⋅ 2.5 =− 6.25 =−6.25
2 2 2
( ) ( ) ( ) ( )
− − 2.5 =−1⋅ − 2.5 =−1⋅ 2.5 =−1⋅ 2.5⋅ 2.5 =−1⋅ 6.25 =−6.25
2 2
( ) ( ) ( ) ( )
15) − − 1.4 =− 1.4 =− 1.4⋅ 1.4 =− 1.96 =−1.96
2 2 2
( ) ( ) ( ) ( )
− − 1.4 =−1⋅ − 1.4 =−1⋅ 1.4 =−1⋅ 1.4⋅ 1.4 =−1⋅ 1.96 =−1.96
2 2
( ) ( ) ( ) ( )
16) − − 0.009 = − 0.009 = − 0.009⋅ 0.009 = − 0.000081
=−0.000081
ili
( 0.009) 1 ( 0.009)
2 2
− − = − ⋅ − =
2
( ) ( ) ( )
=−1⋅ 0.009 =− 0.009⋅ 0.009 =− 0.000081 =−0.000081
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