ZBIRKA POTPUNO RIJEŠENIH ZADATAKA

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Rješenja i kompletni postupak M-8-Kvadriranje i korjenovanje 2. Koristimo pravila: I način: a = a⋅a , − ⋅ − = + −a = a I način po pravilu: 2 a = a ⋅ a ↑ ↓ ↓ 2 ( ) ( ) ( ) 5) − 11 = −11 ⋅ − 11 = + 11⋅ 11 = 121 ( ) ( ) −⋅− =+ 2 ( ) ( ) ( ) ( ) ( ) ( ) 6) − 13 = −13 ⋅ − 13 = + 13⋅ 13 = 169 −⋅− =+ 2 ( ) ( ) ( ) 2 ( ) ( ) ( ) 2 ( ) ( ) ( ) ( ) ( ) ili II način: ( 2 2 2 II način po pravilu: 2 2 ( a) − 11 = 11 = 11⋅ 11 = 121 II način po pravilu: ( ) 7) − 15 = −15 ⋅ − 15 = + 15⋅ 15 = 225 ( ) 8) − 17 = −17 ⋅ − 17 = + 17⋅ 17 = 289 ( ) 2 2 II način po pravilu: II način 9) − 20 = −20 ⋅ − 20 = + 20⋅ 20 = 400 2 ( ) ( ) ( ) 2 ( ) ( ) ( ) II način 2 2 2 2 2 2 − = a ( a) ( a) 2 2 − = a − 13 = 13 = 13⋅ 13 = 169 2 2 − = a − 15 = 15 = 15⋅ 15 = 225 − 17 = 17 = 17⋅ 17 = 289 ( ) 10) − 22 = −22 ⋅ − 22 = + 22⋅ 22 = 484 II način ( ) 11) − 25 = −25 ⋅ − 25 = + 25⋅ 25 = 625 II način ( ) 2 2 − 20 = 20 = 20⋅ 20 = 400 2 2 − 22 = 22 = 22⋅ 22 = 484 2 2 − 25 = 25 = 25⋅ 25 = 625 ) 4
M-8-Kvadriranje i korjenovanje Rješenja i kompletni postupak 2. Koristimo pravila: I način: a = a⋅a , − ⋅ − = + − a = a 2 ( ) ( ) ( ) 12) − 30 = −30 ⋅ − 30 = + 30⋅ 30 = 900 II način ( ) 2 2 − 30 = 30 = 30⋅ 30 = 900 po pravilu: ( ) ( ) II način 2 a a a ( ) ( ) ( ) 2 2 ( ) ( ) 2 2 ( ) ( ) ( ) ( ) ili II način: ( ) 2 2 2 2 ( 1) ( 1) ( 1) = ⋅ dakle: − = − ⋅ − ↑ ↓ ↓ 13) − − 1 =− − 1 =− −1 ⋅ − 1 =− + 1 =−1 2 − − 1 =−1⋅ − 1 =−1⋅ 1 = −11 ⋅ = −1 ( ) ( ) II način ( ) ( ) ( ) 2 2 ( ) ( ) po pravilu: ( a) ( ) ( ) ( ) 14) − − 5 =− − 5 =− −5 ⋅ − 5 =− + 5⋅ 5 =− + 25 =−25 2 2 2 − − 5 =−1⋅ − 5 =−1⋅ 5 =−1⋅5⋅ 5 =−2 ↓ − = a 2 2 ( ) ( ) ili kraće: ( ) ( ) ( ) 2 2 ( ) ( ) 2 2 ( ) ( ) ( ) ( ) ( ) 15) − − 10 =− − 10 =− −10 ⋅ − 10 =− + 10⋅ 10 =− + 100 =−100 − − 10 = − − 10 = − + 100 = −100 II način ( ) ( ) 2 2 2 − − 10 =−1⋅ − 10 =−1⋅ 10 = −1⋅10⋅ 10 = −100 po pravilu: ↓ − = a ( a) 2 2 ( ) ( ) ili kraće: ( ) ( ) ( ) 2 2 ( ) (( ) ) ( ) 2 2 ( ) ( ) ( ) 16) − − 18 =− − 18 =− −18 ⋅ − 18 =− + 18⋅ 18 =− + 324 =−324 − − 18 = − − 18 = − + 324 = −324 II način ( ) ( ) 2 2 2 − − 18 =−1⋅ − 18 =−1⋅ 18 =−1⋅ 324 =−324 po pravilu: ↓ − = ( a) ↑ a 2 2 M-8-rješenja--radna varijanta ( nedovršena) 5 M.I.M.-Sraga --centar za poduku--01-4578-431
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ZBIRKA POTPUNO RIJEŠENIH ZADATAKA

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