TARIFF AGREEMENTS AND NON-RENEWABLE RESOURCE ... - Ivie
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Next, we calculate the difference<br />
nγ<br />
WA(x) S − WA N 2<br />
(x) =<br />
6r − nδ2<br />
8r<br />
<br />
x 2 −<br />
3anγ<br />
9r +5nγ −<br />
anδ <br />
x<br />
4r +3nδ<br />
+ 27a2 nr<br />
2(9r +5nγ) 2 − 2a2 nr<br />
(4r +3nδ) 2 . (61)<br />
The first coefficientofthislinear-quadraticfunctionispositiveif4γ 2 − 3δ 2<br />
is positive. By substitution of γ and δ, see (40) and (57), we obtain<br />
<br />
1 9<br />
n 2 25 ((20cnr +9r2 ) 0.5 − 3r) 2 − 4 <br />
3 ((3cnr + r2 ) 0.5 − r) 2 .<br />
Let us suppose that 4γ 2 − 3δ 2 ≤ 0.Then it must be satisfied that<br />
9<br />
25 ((20cnr +9r2 ) 0.5 − 3r) 2 ≤ 4 3 ((3cnr + r2 ) 0.5 − r) 2 .<br />
Takingthepositivesquarerootandreorderingweobtain<br />
3 √ 3(20cnr +9r 2 ) 0.5 ≤ 10(3cnr + r 2 ) 0.5 +5.59r.<br />
Squaring, reordering terms and squaring again we get the contradiction:<br />
57600c 2 n 2 r 2 + 16172cnr 3 ≤ 0 which establishes that 4γ 2 − 3δ 2 is positive.<br />
Now, we look at the second coefficient of the difference WA S(x) − W A N(x).<br />
This second coefficient is positive if 4γ − 3δ is positive. By substitution we<br />
get now<br />
<br />
2 6<br />
n 10 ((20cnr +9r2 ) 0.5 − 3r) − (3cnr + r 2 ) 0.5 + r<br />
.<br />
Let us suppose that 4γ − 3δ ≤ 0. Then it must be satisfied that<br />
3(20cnr +9r 2 ) 0.5 ≤ 5(3cnr + r 2 ) 0.5 +4r.<br />
Squaring, reordering terms and squaring again we get the contradiction:<br />
11025c 2 n 2 + 3600cnr ≤ 0 which establishes that 4γ − 3δ is positive. Finally,<br />
we compare the independent coefficients. Let us suppose that<br />
Developing this inequality we obtain<br />
27a 2 nr<br />
2(9r +5nγ) − 2a2 nr<br />
2 (4r +3nδ) ≤ 0. 2<br />
432r 2 +648rnδ +243n 2 δ 2 ≤ 324r 2 +360rnγ +100n 2 γ 2 ,<br />
24