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TARIFF AGREEMENTS AND NON-RENEWABLE RESOURCE ... - Ivie

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Next, we calculate the difference<br />

nγ<br />

WA(x) S − WA N 2<br />

(x) =<br />

6r − nδ2<br />

8r<br />

<br />

x 2 −<br />

3anγ<br />

9r +5nγ −<br />

anδ <br />

x<br />

4r +3nδ<br />

+ 27a2 nr<br />

2(9r +5nγ) 2 − 2a2 nr<br />

(4r +3nδ) 2 . (61)<br />

The first coefficientofthislinear-quadraticfunctionispositiveif4γ 2 − 3δ 2<br />

is positive. By substitution of γ and δ, see (40) and (57), we obtain<br />

<br />

1 9<br />

n 2 25 ((20cnr +9r2 ) 0.5 − 3r) 2 − 4 <br />

3 ((3cnr + r2 ) 0.5 − r) 2 .<br />

Let us suppose that 4γ 2 − 3δ 2 ≤ 0.Then it must be satisfied that<br />

9<br />

25 ((20cnr +9r2 ) 0.5 − 3r) 2 ≤ 4 3 ((3cnr + r2 ) 0.5 − r) 2 .<br />

Takingthepositivesquarerootandreorderingweobtain<br />

3 √ 3(20cnr +9r 2 ) 0.5 ≤ 10(3cnr + r 2 ) 0.5 +5.59r.<br />

Squaring, reordering terms and squaring again we get the contradiction:<br />

57600c 2 n 2 r 2 + 16172cnr 3 ≤ 0 which establishes that 4γ 2 − 3δ 2 is positive.<br />

Now, we look at the second coefficient of the difference WA S(x) − W A N(x).<br />

This second coefficient is positive if 4γ − 3δ is positive. By substitution we<br />

get now<br />

<br />

2 6<br />

n 10 ((20cnr +9r2 ) 0.5 − 3r) − (3cnr + r 2 ) 0.5 + r<br />

.<br />

Let us suppose that 4γ − 3δ ≤ 0. Then it must be satisfied that<br />

3(20cnr +9r 2 ) 0.5 ≤ 5(3cnr + r 2 ) 0.5 +4r.<br />

Squaring, reordering terms and squaring again we get the contradiction:<br />

11025c 2 n 2 + 3600cnr ≤ 0 which establishes that 4γ − 3δ is positive. Finally,<br />

we compare the independent coefficients. Let us suppose that<br />

Developing this inequality we obtain<br />

27a 2 nr<br />

2(9r +5nγ) − 2a2 nr<br />

2 (4r +3nδ) ≤ 0. 2<br />

432r 2 +648rnδ +243n 2 δ 2 ≤ 324r 2 +360rnγ +100n 2 γ 2 ,<br />

24

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