TÌM HIỂU VỀ CHUẨN ĐỘ ĐA AXIT - ĐA BAZƠ
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Áp dụng định luật bảo toàn proton với mức không với<br />
H 2 PO 4- , H 2 O . Ta có:<br />
⇔<br />
[ H ] = [ O H ] + [ H P O ] − [ H P O ]<br />
+ − 2 −<br />
4 3 4<br />
-<br />
W K<br />
a2<br />
.[H<br />
2<br />
P O<br />
4<br />
] -1 -<br />
h = + -K<br />
a1.h .[H<br />
2<br />
P O<br />
4<br />
]<br />
h h<br />
⇒ h =<br />
W + K .[H P O ]<br />
−<br />
a 2 2 4<br />
− 1<br />
−<br />
a 1 2<br />
P O<br />
4<br />
1 + K .[H ]<br />
Mặt khác: K a 2 .C >> W −<br />
K .[H P O ]<br />
5<br />
⇒ h = 1 + K .[H ]<br />
=<br />
a 2 2 4<br />
− 1<br />
−<br />
a 1 2<br />
P O<br />
4<br />
⇒ pH = 4,84<br />
1, 4 5 5 .1 0<br />
−
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