TÌM HIỂU VỀ CHUẨN ĐỘ ĐA AXIT - ĐA BAZƠ
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Ta có:<br />
C o :<br />
[]<br />
H 2<br />
A + NaOH → NaHA + H 2<br />
O<br />
1 4<br />
35 175<br />
1<br />
175<br />
4<br />
175<br />
Nếu coi K a1 >>K a2 , thì chỉ xét cân bằng:<br />
K a 1<br />
C o :<br />
[]:<br />
−3 −3<br />
4<br />
10 .(10 + )<br />
= 175 = 5, 06.10<br />
1 −3<br />
( −10 )<br />
175<br />
H A ⇌ HA + H K a<br />
1<br />
175<br />
−3<br />
− +<br />
2 1<br />
1<br />
175<br />
1 4<br />
175<br />
4<br />
175<br />
−3<br />
−3<br />
−10<br />
+ 10<br />
3<br />
K a1 >> K a2<br />
thỏa giả thiết đặt ra.<br />
10 −
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