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Probability Distributions - Oxford University Press

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Excel solution—Example 5.10<br />

The Excel solution is ill ustrated in Figure 5.13.<br />

➜ Excel Solution<br />

Mean = Cell C5 Value<br />

Standard deviation Cell C6 Value<br />

X = Cell C8 Value<br />

P(X 110) = Cell C12 Formula: =1–C10<br />

From Excel, the NORMDIST() function can be used to calculate P(X ≥ 110) = 0.02275.<br />

❉ Interpretation We observe that the probability that an individual tube length is at<br />

least 110 cms is 0.02275 or 2.3%.<br />

Example 5.11<br />

Figure 5.13<br />

Calculate the probability that X lies between 85 and 105 cms for the problem outlined in<br />

Example 5.10.<br />

In this example we are<br />

required to calculate P(85<br />

≤ X ≤ 105) which represents<br />

the area shaded in<br />

Figure 5.14.<br />

The value of P(85 ≤ X<br />

≤ 105) can be calculated<br />

using Excel’s NORMDIST()<br />

function.<br />

Figure 5.14<br />

P(85

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