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Wavelets - Caltech Multi-Res Modeling Group

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and the function can be reconstructed as:<br />

f (t) =<br />

1X<br />

i=0<br />

wi Wi(t)<br />

Figures I.7 and I.8 show the coefficients of the Walsh basis for both of the above signals.<br />

5<br />

4<br />

3<br />

2<br />

1<br />

0<br />

-1<br />

-1<br />

-2<br />

-3<br />

0123456<br />

INTRODUCTION 9<br />

0 5 10 15 20 25 30<br />

Figure I.7: Walsh coefficients for signal 1.<br />

0 5 10 15 20 25 30<br />

Figure I.8: Walsh coefficients for signal 2.<br />

Note that since the original signals have discontinuities only at integral values, the signals are exactly<br />

represented by the first 32 Walsh bases at most. But we should also note that in this example, as well as<br />

would be the case for a Fourier transform, the presence of a single discontinuity at 21 for signal 1 introduces<br />

the highest “frequency” basis, and it has to be added globally for all t. In general cases the coefficients for<br />

each basis function decrease rapidly as the order increases, and that usually allows for a simplification (or<br />

compression) of the representation of the original signal by dropping the basis functions whose coefficients<br />

are small (obviously with loss of information if the coefficients are not 0).<br />

Siggraph ’95 Course Notes: #26 <strong>Wavelets</strong>

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