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Equilibrio de un cuerpo rígido

Equilibrio de un cuerpo rígido

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Solución<br />

Ecuaciones <strong>de</strong> <strong>Equilibrio</strong><br />

∑ M x =0 ;T C (2m)−981 N (1m )+B Z (2m)=0<br />

∑ M y =0 ;<br />

300 N (1 .5m )+981 N (1 .5m )−B z<br />

(3m )− A z<br />

(3m )−200 N . m=0<br />

• La componentes <strong>de</strong> la fuerza en B se pue<strong>de</strong>n eliminar<br />

si se usan los ejes x’, y’, z’<br />

∑ M x'<br />

=0 ; 981 N (1m )+300 N (2m)− A z<br />

(2m)=0<br />

∑ M y' =0 ;<br />

−300 N (1. 5m )−981 N (1 . 5m)200 N . m+T C<br />

(3m)=0

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