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10-RLC krugovi.pdf

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Iε / RR− tLε ⎛= 1− e I = ⎜1−eR ⎝Nakon dovoljno dugo vremena −R tL⎞⎟⎠EXPR− tL= e =t = 0 I = I 0 = ε/R I I ⎛01 e − L= ⎜ −⎝tt⎛ − ⎞ ⎛ − ⎞L / RI = I0 ⎜1− e ⎟ = I0⎜1−e τ⎟⎝ ⎠ ⎝ ⎠1R tLeza t → ∞ ⇒ EXP → 0R t⎞⎟⎠τ = L/R = vremenska konstanta= vrijeme potrebno da strujadostigne 63,2% svoje konačnevrijednosti (t = τ)( − 1)I = I 1− e = 0,632 I0 0

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